从JSON字符串创建Hashmap

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从java中的json字符串创建一个hashmap?

我有像{"phonetype":"N95","cat":"WP"}的json字符串,想要转换成标准的Hashmap。

我该怎么做?

答案

解析JSONObject并创建HashMap

public static void jsonToMap(String t) throws JSONException {

        HashMap<String, String> map = new HashMap<String, String>();
        JSONObject jObject = new JSONObject(t);
        Iterator<?> keys = jObject.keys();

        while( keys.hasNext() ){
            String key = (String)keys.next();
            String value = jObject.getString(key); 
            map.put(key, value);

        }

        System.out.println("json : "+jObject);
        System.out.println("map : "+map);
    }

测试输出:

json : {"phonetype":"N95","cat":"WP"}
map : {cat=WP, phonetype=N95}
另一答案
public Map<String, String> parseJSON(JSONObject json, Map<String, String> dataFields) throws JSONException {
        Iterator<String> keys = json.keys();
        while (keys.hasNext()) {
            String key = keys.next();
            String val = null;
            try {
                JSONObject value = json.getJSONObject(key);
                parseJSON(value, dataFields);
            } catch (Exception e) {
                if (json.isNull(key)) {
                    val = "";
                } else {
                    try {
                        val = json.getString(key);
                    } catch (Exception ex) {
                        System.out.println(ex.getMessage());
                    }
                }
            }

            if (val != null) {
                dataFields.put(key, val);
            }
        }
        return dataFields;
    }
另一答案

将Json解析为HashMap的最佳方法

public static HashMap<String, String> jsonToMap(JSONObject json) throws JSONException {
            HashMap<String, String> map = new HashMap<>();
            try {
                Iterator<String> iterator = json.keys();

                while (iterator.hasNext()) {
                    String key = iterator.next();
                    String value = json.getString(key);
                    map.put(key, value);
                }

                return map;
            } catch (JSONException e) {
                e.printStackTrace();
            }
            return null;
        }
另一答案

你可以用杰克逊来做这件事。我还没有找到一个简单的Gson解决方案。

其中data_map.json是JSON(对象)资源文件 和data_list.json是一个JSON(数组)资源文件。

import java.io.File;
import java.io.IOException;
import java.net.MalformedURLException;
import java.net.URISyntaxException;
import java.net.URL;
import java.util.List;
import java.util.Map;
import java.util.Scanner;

import com.fasterxml.jackson.core.JsonGenerationException;
import com.fasterxml.jackson.core.JsonParseException;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;

/**
 * Based on:
 * 
 * http://www.mkyong.com/java/how-to-convert-java-map-to-from-json-jackson/
 */
public class JsonLoader {
    private static final ObjectMapper OBJ_MAPPER;
    private static final TypeReference<Map<String,Object>> OBJ_MAP;
    private static final TypeReference<List<Map<String,Object>>> OBJ_LIST;

    static {
        OBJ_MAPPER = new ObjectMapper();
        OBJ_MAP = new TypeReference<Map<String,Object>>(){};
        OBJ_LIST = new TypeReference<List<Map<String,Object>>>(){};
    }

    public static void main(String[] args) {
        try {
            System.out.println(jsonToString(parseJsonString(read("data_map.json", true))));
            System.out.println(jsonToString(parseJsonString(read("data_array.json", true))));
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    private static final Object parseJsonString(String jsonString) {
        try {
            if (jsonString.startsWith("{")) {
                return readJsonObject(jsonString);
            } else if (jsonString.startsWith("[")) {
                return readJsonArray(jsonString);
            }
        } catch (JsonGenerationException e) {
            e.printStackTrace();
        } catch (JsonMappingException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        return null;
    }

    public static String jsonToString(Object json) throws JsonProcessingException {
        return OBJ_MAPPER.writerWithDefaultPrettyPrinter().writeValueAsString(json);
    }

    private static final Map<String,Object> readJsonObject(String jsonObjectString) throws JsonParseException, JsonMappingException, IOException {
        return OBJ_MAPPER.readValue(jsonObjectString, OBJ_MAP);
    }

    private static final List<Map<String,Object>> readJsonArray(String jsonArrayString) throws JsonParseException, JsonMappingException, IOException {
        return OBJ_MAPPER.readValue(jsonArrayString, OBJ_LIST);
    }

    public static final Map<String,Object> loadJsonObject(String path, boolean isResource) throws JsonParseException, JsonMappingException, MalformedURLException, IOException {
        return OBJ_MAPPER.readValue(load(path, isResource), OBJ_MAP);
    }

    public static final List<Map<String,Object>> loadJsonArray(String path, boolean isResource) throws JsonParseException, JsonMappingException, MalformedURLException, IOException {
        return OBJ_MAPPER.readValue(load(path, isResource), OBJ_LIST);
    }

    private static final URL pathToUrl(String path, boolean isResource) throws MalformedURLException {
        if (isResource) {
            return JsonLoader.class.getClassLoader().getResource(path);
        }

        return new URL("file:/" + path);
    }

    protected static File load(String path, boolean isResource) throws MalformedURLException {
        return load(pathToUrl(path, isResource));
    }

    protected static File load(URL url) {
        try {
            return new File(url.toURI());
        } catch (URISyntaxException e) {
            return new File(url.getPath());
        }
    }

    public static String read(String path, boolean isResource) throws IOException {
        return read(path, "UTF-8", isResource);
    }

    public static String read(String path, String charset, boolean isResource) throws IOException {
        return read(pathToUrl(path, isResource), charset);
    }

    @SuppressWarnings("resource")
    public static String read(URL url, String charset) throws IOException {
        return new Scanner(url.openStream(), charset).useDelimiter("\A").next();
    }
}

Extra

以下是Dheeraj Sachan示例的完整代码。

import java.io.File;
import java.io.IOException;
import java.io.Serializable;
import java.net.MalformedURLException;
import java.net.URISyntaxException;
import java.net.URL;
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.HashMap;
import java.util.Iterator;
import java.util.List;
import java.util.Map.Entry;
import java.util.Scanner;

import com.fasterxml.jackson.annotation.JsonAutoDetect;
import com.fasterxml.jackson.annotation.PropertyAccessor;
import com.fasterxml.jackson.core.JsonParseException;
import com.fasterxml.jackson.databind.DeserializationFeature;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.PropertyNamingStrategy;

public class JsonHandler {
    private static ObjectMapper propertyMapper;

    static {
        final DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

        propertyMa

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