C# 如何得到一XML文件中指定的节点属性值

Posted 2023-05-02

想要个函数，参数是两个：a 节点名 b 属性名 然后返回该节点的指定属性值。 恳求大虾们提供帮助。

参考技术A //xmlFile是xml文件,nodeName是节点名,attributeName是节点的属性名,因为节点名是可以重复的,所以用list存放返回值
public
List<string>
GetAttribute(string
xmlFile,
string
nodeName,
string
attributeName)

List<string>
retList
=
new
List<string>();
XmlDocument
xx
=
new
XmlDocument();
xx.Load(xmlFile);
XmlNodeList
xxList
=
xx.GetElementsByTagName(nodeName);
foreach
(XmlNode
xxNode
in
xxList)

retList.Add(xxNode.Attributes[attributeName].Value);

return
retList;

删除log文件末尾中指定的行数

        /// <summary>
        /// 删除log文件末尾中指定的行数
        /// </summary>
        /// <param name="file">文件路径</param>
        /// <param name="line">删除的行数</param>
        public static void deleteLogToLine(string file,int line)
        {
            System.IO.StreamReader st= new StreamReader(file, System.Text.Encoding.Default);

            int lineCount = 0;//总行数
            List<string> data = new List<string>();
            while (true)
            {
                string str = st.ReadLine();
                if (str == null || str.Length == 0) break;
                data.Add(str);
                lineCount++;
            }
            st.Close();
            st.Dispose();

            StreamWriter sw = new StreamWriter(file, false);
            for (int i = 0; i < data.Count - line; i++)
            {
                sw.WriteLineAsync(data[i]);
            }
            sw.Flush();
            sw.Close();
        }