如何循环我的问题？ Javascript数字猜测游戏

Posted 2021-04-15

新程序员在这里 - 我正在尝试创建一个数字猜谜游戏。如果我猜得太高，它会告诉我“太高了，再猜一次。”如果我猜得太低，它会告诉我“太低了，再猜一次。”如果我猜错了它告诉我正确的话。但我只能在每个方向猜出1个错误答案。我搜索并搜索了几乎所有的东西（if / else / while）

我知道这对于有经验的程序员来说可能是一个简单的修复。请帮忙。谢谢 - -

var secretNumber = 53;

var guess = prompt('Guess a number');


if (guess == (53)) {
alert("Yes you got it! 53 is the right answer!")}

while (guess < (53)) {
var guess = prompt('Too Low, Guess again');
}

while (guess > (53)) {
var guess = prompt('Too High, Guess again');
}

答案

试试这个：

var secretNumber = 53;

var high = false;
var low = false;
var done = false;

var guess = prompt('Guess a number');
while (!done) {
  if (guess === secretNumber) {
    alert("Yes you got it! " + secretNumber + " is the right answer!");
    done = true;
  } else if (guess < secretNumber) {
    if (low) {
      alert('You have failed');
      done = true;
    } else {
      low = true;
      guess = prompt('Too Low, Guess again');
    }
  } else if (guess > secretNumber) {
    if (high) {
      alert('You have failed');
      done = true;
    } else {
      high = true;
      guess = prompt('Too High, Guess again');
    }
  }
}

这不是最佳的，但对于这个练习应该这样做。