arduino_1.0.1的串口监视器应该怎么用？

Question

我是Node.JS和Arduino的新手。我有一个带有温度传感器的Arduino设置。我正在用Arduino读取温度值。我的串口监视器输出如下：

串口监视器：

0.05
0.10
0.15
0.20
0.25
0.30
0.34

我使用serialport将数据从Arduino发送到我的终端，然后以图表形式在我的webbrowser上显示数据。我正在使用express和socket.io。这是与index.js的arduino和浏览器的连接。还有一个index.html

index.js：


    var express = require('express');

    var app = express();
    var http = require('http').Server(app);
    var server = http.listen(4000, "0.0.0.0", () => { //Start the server, listening on port 4000.
        console.log("Listening to requests on port 4000...");
    })

    var io = require('socket.io')(server); //Bind socket.io to our express server.

    app.use(express.static('public')); //Send index.html page on GET /

    const SerialPort = require('serialport');
    const Readline = SerialPort.parsers.Readline;
    const port = new SerialPort('/dev/ttyUSB0'); //Connect serial port to port COM3. Because my Arduino Board is connected on port COM3. See yours on Arduino IDE -> Tools -> Port
    const parser = port.pipe(new Readline({delimiter: '\r\n'})); //Read the line only when new line comes.
    parser.on('data', (temp) => { //Read data
        console.log(temp);
        var today = new Date();
        io.sockets.emit('temp', {date: today.getDate()+"-"+today.getMonth()+1+"-"+today.getFullYear(), time: (today.getHours())+":"+(today.getMinutes()), temp:temp}); //emit the datd i.e. {date, time, temp} to all the connected clients.
    });

    io.on('connection', (socket) => {
        console.log("Someone connected."); //show a log as a new client connects.
    })

从串口接收的温度数据Arduino显示在index.html（webbrowser）中。

index.html的：

<!DOCTYPE html>
<html>
    <head>
        <title>Temperature Plot</title>
        <meta name="viewport" content="width=device-width, initial-scale=1.0">
    </head>
    <body>
        <h1>Temperature Graph</h1>
        <h4>Date: <span id="date"></span></h4>
        <div class="chart-container" style="position: relative; width:75vw; margin: auto;">
            <canvas id="myChart"></canvas>
        </div>
        <link href="https://fonts.googleapis.com/css?family=Lato" rel="stylesheet">
        <script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.4.0/Chart.min.js"></script>
        <script src="https://cdnjs.cloudflare.com/ajax/libs/socket.io/2.0.4/socket.io.js"></script>
        <script>
            var socket = io.connect('http://192.168.1.3:4000'); //connect to server
            var ctx = document.getElementById('myChart').getContext('2d');
            var chart = new Chart(ctx, {
                // The type of chart we want to create
                type: 'line',
                // The data for our dataset
                data: {
                labels: [],
                datasets: [{
                    label: "Temperature",
                    borderColor: "#FF5733",
                    data: [],
                    fill: false,
                    pointStyle: 'circle',
                    backgroundColor: '#3498DB',
                    pointRadius: 5,
                    pointHoverRadius: 7,
                    lineTension: 0,
                }]
                },
                // Configuration options go here
                options: {}

            });
            socket.on('temp', function(data) { //As a temp data is received
                console.log(data.temp);
                document.getElementById('date').innerHTML = data.date; //update the date
                if(chart.data.labels.length != 15) { //If we have less than 15 data points in the graph
                    chart.data.labels.push(data.time);  //Add time in x-asix
                    chart.data.datasets.forEach((dataset) => {
                        dataset.data.push(data.temp); //Add temp in y-axis
                    });
                }
                else { //If there are already 15 data points in the graph.
                    chart.data.labels.shift(); //Remove first time data
                    chart.data.labels.push(data.time); //Insert latest time data
                    chart.data.datasets.forEach((dataset) => {
                        dataset.data.shift(); //Remove first temp data
                        dataset.data.push(data.temp); //Insert latest temp data
                    });
                }
                chart.update(); //Update the graph.
            });
        </script>
    </body>
    <style>
        h1 {
            text-align: center;
            font-family: 'Lato', sans-serif;
        }
        h4 {
            text-align: center;
            font-family: 'Lato', sans-serif;
        }
        p {
            text-align: center;
            font-family: 'Lato', sans-serif;
        }
    </style>
</html>

如果Arduino上只有1个传感器温度，一切正常，但是当我添加另一个带有串行监视器结果的温度传感器，如下所示，使传感器数据无法以index.html的形式出现在图表中，而控制台浏览器也只能显示与串行监视器相同的数据。

带2个温度传感器的串行监视器（温度传感器之间的读数结果用空格分隔）

0.05 1.00
0.10 1.00
0.15 0.99
0.20 0.98
0.25 0.97
0.30 0.96
0.34 0.94

我已经尝试解决这个问题差不多一个星期了，我已经尝试了很多方法来解决这个问题，但它没有用，我确实需要你的帮助

arduino代码：

double x; //I simulate 2 temperature sensor values
    void setup() {
      Serial.begin(115200);
      x = 0;
    }

    void loop() {  
      Serial.print(sin(x));
      Serial.print(" ");
      Serial.println(cos(x));
      delay(50);

      // seting batasan input fungsi sinus
      x += 0.05;
      if(x>= 2*3.14){
        x = 0;
      }  
    }

arduino_1.0.1的串口监视器应该怎么用？

使用javascript和socket.io从串口显示多个传感器数据

第一名

第二名

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