JS中的groupBy方法
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最近工作中需要写一些运营数据报表的页面,后端返回的数据都是未处理过的json,所以,大量的运算任务交给了前端来做,这其中有一个功能就是对数据进行分组,一开始我自己也尝试写了一些,但代码量比较大,显得很繁琐,直到后来在stackoverflow上看到了某位大牛写的方法,非常简洁优雅,代码如下:
function groupBy( array , f ) { let groups = {}; array.forEach( function( o ) { let group = JSON.stringify( f(o) ); groups[group] = groups[group] || []; groups[group].push( o ); }); return Object.keys(groups).map( function( group ) { return groups[group]; }); } let list = [ {"name": "John","Average":15,"High":10,"DtmStamp":1358226000000}, {"name": "Jane","Average":16,"High":92,"DtmStamp":1358226000000}, {"name": "Jane","Average":17,"High":45,"DtmStamp":1358226000000}, {"name": "John","Average":18,"High":87,"DtmStamp":1358226000000}, {"name": "Jane","Average":15,"High":10,"DtmStamp":1358226060000}, {"name": "John","Average":16,"High":87,"DtmStamp":1358226060000}, {"name": "John","Average":17,"High":45,"DtmStamp":1358226060000}, {"name": "Jane","Average":18,"High":92,"DtmStamp":1358226060000} ]; let sorted = groupBy(list, function(item){ return [item.name]; }); console.log(sorted);
- 函数groupBy有两个形参,一为对象数组,二为匿名函数(该函数功能:返回对象的某个指定属性的属性值并存放在数组中);
- groupBy函数内,先创建一个空对象;
- 然后forEach遍历对象数组,遍历时要执行的函数中只有一个形参o(数组中的每个元素);
- 由于下面函数调用是想用name来分组,因此let group = JSON.stringify( f(o) ),相当于先获取到对象数组list中的name属性对应的属性值并放入数组中:["John"],然后再将属性值转换为json字符串:‘["John"]‘;
- groups[group] = groups[group] || [],在js中对象也是关联数组,因此这里相当于做了两件事,一是把group作为groups的key,二是将对应的value初始化,第一次执行为空数组,循环执行时找到相同的name时保持不变;
- groups[group].push( o ),这句相当于把list中每个对象压入数组中作为value;
- 最后,Object.keys(groups)是取出groups对象中的所有key,然后遍历一个个key组成的新数组,返回分好了组的二维数组,至此大功告成~~~
[ [ { name: ‘John‘, Average: 15, High: 10, DtmStamp: 1358226000000 }, { name: ‘John‘, Average: 18, High: 87, DtmStamp: 1358226000000 }, { name: ‘John‘, Average: 16, High: 87, DtmStamp: 1358226060000 }, { name: ‘John‘, Average: 17, High: 45, DtmStamp: 1358226060000 } ], [ { name: ‘Jane‘, Average: 16, High: 92, DtmStamp: 1358226000000 }, { name: ‘Jane‘, Average: 17, High: 45, DtmStamp: 1358226000000 }, { name: ‘Jane‘, Average: 15, High: 10, DtmStamp: 1358226060000 }, { name: ‘Jane‘, Average: 18, High: 92, DtmStamp: 1358226060000 } ] ]
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