js求数组的交集/并集/差集/去重

Posted 2021-01-30 时空旅人

      1.求交集
　　　　var arr1 = [{name:‘name1‘,id:1},{name:‘name2‘,id:2},{name:‘name3‘,id:3}];
      var arr1Id = [1,2,3]
      var arr2 = [{name:‘name1‘,id:1},{name:‘name2‘,id:2},{name:‘name3‘,id:3},{name:‘name4‘,id:4},{name:‘name5‘,id:5}];
      var result = arr2.filter(function(v){
            return arr1Id.indexOf(v.id)!==-1 // 利用filter方法来遍历是否有相同的元素
        })
      console.log(result);

 

      2.求并集
　　　　let arr1 = [{name:‘name1‘,id:1},{name:‘name2‘,id:2},{name:‘name3‘,id:3}];
      let arr2 = [{name:‘name1‘,id:1},{name:‘name4‘,id:4},{name:‘name5‘,id:5}];
      let arr3 = arr1.concat(arr2);
      let result = [];
      var obj = [];
      result = arr3.reduce(function(prev, cur, index, arr) {
        console.log(prev, cur);
        obj[cur.id] ? ‘‘ : obj[cur.id] = true && prev.push(cur);
        return prev;
      }, []);
      console.log(result);

 

　　　　3.求差集
　　　　let arr1 = [{name:‘name1‘,id:1},{name:‘name2‘,id:2},{name:‘name3‘,id:3}];
      let arr1Id = [1,2,3];
      let arr2 = [{name:‘name1‘,id:1},{name:‘name4‘,id:4},{name:‘name5‘,id:5}];
      let arr2Id = [1,4,5];
      let arr3 = arr1.concat(arr2);
      let result = arr3.filter(function(v){
          return arr1Id.indexOf(v.id)===-1 || (arr2Id.indexOf(v.id)===-1)
      })
      console.log(result);

　　

      4.去重
　　　　let arr = [{name:‘name1‘,id:1},{name:‘name2‘,id:2},{name:‘name3‘,id:3},{name:‘name1‘,id:1},{name:‘name4‘,id:4},{name:‘name5‘,id:5}];
      var obj = [];
      let result = arr.reduce(function(prev, cur, index, arr) {
        console.log(prev, cur);
        obj[cur.id] ? ‘‘ : obj[cur.id] = true && prev.push(cur);
        return prev;
      }, []);