JS判断提交表单不能为空 等的验证

Posted 2021-01-29 Sharpest

转自：https://blog.csdn.net/qiu512300471/article/details/23259811

<script type="text/javascript">
function beforeSubmit(form){
if(form.username.value==‘‘){
alert(‘用户名不能为空！‘);
form.username.focus();
return false;
}
if(form.password.value==‘‘){
alert(‘密码不能为空！‘);
form.password.focus();
return false;
}
if(form.password.value.length<6){
alert(‘密码至少为6位，请重新输入！‘);
form.password.focus();
return false;
}
if(form.password.value!=form.password2.value) {
alert(‘你两次输入的密码不一致，请重新输入！‘);
form.password2.focus();
return false;
}
return true;
}
</script>

<fieldset>
   <legend>用户注册</legend>
    <form method="post" name="form" action="user.do?method=register" onSubmit="return beforeSubmit(this);">
     <table border="1" width="100%" cellspacing="0" cellpadding="0">
      <tr><td><label>用户名：<input type="text" name="username" value=""></label></td></tr>
      <tr><td><label>密   码：<input type="password" name="password" value=""></label></td></tr>
      <tr><td><label>重复密码：<input type="password" name="password2" value=""></label></td></tr>
      <tr><td><input value="注册" type="submit"> <input type="reset" value="重置"></td></tr>      
     </table>
    </form>
</fieldset>