XML转JSON

Posted 2021-01-18 soulbky

 1               XmlDocument doc = new XmlDocument();
 2                 doc.Load(path);
 3                 string strXml = doc.InnerXml;
 4                 XmlNode node = doc.SelectSingleNode("data");  //data  根节点名称
 5                 string result = Newtonsoft.Json.JsonConvert.SerializeXmlNode(node);
 6 
 7 
 8                 //string pathFile = System.IO.Path.GetFullPath("../../file/josn.txt");
 9                 FileStream fs = new FileStream(@"../../file/josn.txt", FileMode.Create);
10 
11                 
12                 //获得字节数组
13                 byte[] data = System.Text.Encoding.Default.GetBytes(result); 
14                 //开始写入
15                 fs.Write(data, 0, data.Length);
16                 //清空缓冲区、关闭流
17                 fs.Flush();
18                 fs.Close();