mysql todays 根据时间查询

Posted 2023-02-18 无敌的星哥哥

1、利用to_days函数查询今天的数据：

  select * from 表名 where to_days(时间字段名) = to_days(now());

to_days函数：返回从0000年（公元1年）至当前日期的总天数。
2、昨天

  SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) – TO_DAYS( 时间字段名) <= 1

3.7天

  SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)

4.近30天

  SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)

5.本月

  SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, ‘%Y%m' ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m' )

6.上一月

  SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m' ) , date_format( 时间字段名, ‘%Y%m' ) ) =1

#查询本季度数据

  select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());

#查询上季度数据

 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));

#查询本年数据
select * from ht_invoice_information where YEAR(create_date)=YEAR(NOW());
#查询上年数据
select * from ht_invoice_information where year(create_date)=year(date_sub(now(),interval 1 year));

查询当前这周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now());
查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now())-1;
查询当前月份的数据
select name,submittime from enterprise where date_format(submittime,’%Y-%m’)=date_format(now(),’%Y-%m’)
查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查询上个月的数据
select name,submittime from enterprise where date_format(submittime,’%Y-%m’)=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),’%Y-%m’)
select * from user where DATE_FORMAT(pudate, ‘ %Y%m ‘ ) = DATE_FORMAT(CURDATE(), ‘ %Y%m ‘ ) ;
select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,’%y-%m-%d’)) = WEEKOFYEAR(now())
select *
from user
where MONTH (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = MONTH (now())
select *from [ user ]where YEAR (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = YEAR (now())and MONTH (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = MONTH (now())
select *from [ user ]where pudate between 上月最后一天and 下月第一天where date(regdate) = curdate();
select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())
SELECT date( c_instime ) ,curdate( )
FROM t_score
WHERE 1
LIMIT 0 , 30`