2018.7.27 Json与Java相互转换
Posted Legend
tags:
篇首语：本文由小常识网(cha138.com)小编为大家整理，主要介绍了2018.7.27 Json与Java相互转换相关的知识，希望对你有一定的参考价值。
Json.jsp
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<%@taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
<script type="text/javascript" src="js/jquery-3.2.1.js"></script>
<script type="text/javascript" >
$(function(){
$.post("JsonServlet",{method:"entityJson"},function(msg){
//console.log(msg);//调试
//接收过来是String 要转成对象才能点里面的属性
var json = JSON.parse(msg); //字符串---->对象
$("#Uname").val(json.uname);//给文本框中value赋值
$("#num").val(json.uid);//给文本框中value赋值
$("#addr").html(json.address);
});
$.post("JsonServlet",{method:"jsonList"},function(pList){
//console.log(msg);//调试
//接收过来是String 要转成对象才能点里面的属性
var pObj = $.parseJSON(pList);//字符串----->数组对象
$.each(pObj,function(i,p){
var li = "<li>"+p.uid+"</li>"+"<li>"+p.uname+"</li>"+"<li>"+p.address+"</li>"+"<br/>";
$("#myUl").append(li);
});
});
$("#btn").click(function(){
var url = "JsonServlet";
var data ={"method":"jsonMap"};
$.post(url,data,function(pMap){
var personMap = $.parseJSON(pMap);//json集合字符串转json对象
$.each(personMap,function(key,value){
$.each(value,function(i,person){
var li = "<li>"+person.uid+person.uname+person.address+"</li>";
$("#myMap").append(li);
});
});
});
});
})
</script>
</head>
<body>
<h3>Java实体(字符串)转JSON对象 JSON.parse(msg);</h3>
ID:<input type="text" id="num"><br/>
Name:<input type="text" id="Uname" ><br/>
Address:<span id="addr" ></span>
<hr>
<h3>Java集合转JSON数组对象 $.parseJSON(pList)</h3>
<ul id="myUl">
</ul>
<hr>
<h3>Map集合转JSON对象</h3>
<button id=‘btn‘>获取Map集合数据</button>
<ul id="myMap">
</ul>
</body>
</html>JsonServlet
package servlet;
import java.io.IOException;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.collections.map.HashedMap;
import domain.Person;
import net.sf.json.JSONArray;
import net.sf.json.JSONObject;
@WebServlet("/JsonServlet")
public class JsonServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doPost(request, response);
}
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String method = request.getParameter("method");
if(method.equals("entityJson")) {
//设置编码格式 不然会显示乱码
response.setContentType("text/html;charset=utf-8");
Person p = new Person(1001, "张三", "男", "广西");
// 1. java实体转json对象
JSONObject jsonObj = JSONObject.fromObject(p);
//发送数据 字符串形式
response.getWriter().println(jsonObj);
System.out.println(jsonObj);
}else if(method.equals("jsonList")){
//设置编码格式 不然会显示乱码
response.setContentType("text/html;charset=utf-8");
List<Person> pList = new ArrayList<Person>();
Person p1 = new Person(1001, "张三", "男", "广西");
Person p2 = new Person(1002, "李四", "女", "广东");
Person p3 = new Person(1003, "王五", "男", "四川");
pList.add(p1);
pList.add(p2);
pList.add(p3);
JSONArray jsonObject = JSONArray.fromObject(pList);
System.out.println("集合长度是"+jsonObject.size());
response.getWriter().println(jsonObject);
}else if(method.equals("jsonMap")){
//设置编码格式 不然会显示乱码
response.setContentType("text/html;charset=utf-8");
Map<String,Person> mp = new HashMap<String,Person>();
mp.put("管理员", new Person(1001, "张三", "男", "广西"));
mp.put("游客", new Person(1002, "张四", "男", "广西"));
JSONArray jsonMap = JSONArray.fromObject(mp);
//发送数据
response.getWriter().println(jsonMap);
}
}
}
以上是关于2018.7.27 Json与Java相互转换的主要内容，如果未能解决你的问题，请参考以下文章