C#直接解析Json键值对

Posted 2020-11-19 陋室铭

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string test_json = "{"name":"tom","nickname":"tony","sex":"male","age":20,"email":"[email protected]"}";  
    var o = JObject.Parse(yourJsonString);  
      
                foreach (JToken child in o.Children())  
                {  
                    var property1 = child as JProperty;  
                    MessageBox.Show(property1.Name + ":" + property1.Value);  
    }  


多层Json


    var o = JObject.Parse(yourJsonString);  
      
    foreach (JToken child in o.Children())  
    {  
        //var property1 = child as JProperty;  
        //MessageBox.Show(property1.Name + ":" + property1.Value);  
        foreach (JToken grandChild in child)  
        {  
            foreach (JToken grandGrandChild in grandChild)  
            {  
                var property = grandGrandChild as JProperty;  
                if (property != null)  
                {  
                    MessageBox.Show(property.Name + ":" + property.Value);  
                }  
            }  
        }  
    }