json解析框架

Posted 2020-11-14

2、需要在App.java中继承WebMvcConfigurerAdapter重写方法：configureMessageConverters 添加我们自己定义的json解析框架;
2.1 @Bean注入第三方的json解析框架：

@Bean
public HttpMessageConverters fastJsonHttpMessageConverters() {
    // 1、需要先定义一个 convert 转换消息的对象;
    FastJsonHttpMessageConverter fastConverter = new FastJsonHttpMessageConverter();

    //2、添加fastJson 的配置信息，比如：是否要格式化返回的json数据;
    FastJsonConfig fastJsonConfig = new FastJsonConfig();
    fastJsonConfig.setSerializerFeatures(SerializerFeature.PrettyFormat);

    //3、在convert中添加配置信息.
    fastConverter.setFastJsonConfig(fastJsonConfig);

    HttpMessageConverter<?> converter = fastConverter;
    return new HttpMessageConverters(converter);
}

  /**
     * Spring Boot默认使用的json解析框架是jackson
     * @return
     */
    @RequestMapping("/getDemo")
    public person getDemo(){
        person demo = new person();
        demo.setAge(1);
        demo.setName("张三");
        demo.setCreateTime(new Date());
        demo.setRemarks("这是备注信息");
        return demo;
    }