JAVA代码解析String字符串(json格式的)

Posted 2020-11-10 小毛喵喵

java解析String字符串(json格式)

　　需要jar包：json-lib-2.4-jdk15.jar

一、

　　String str = "{\"name\":\"zhangsan\",\"password\":\"zhangsan123\",\"email\":\"[email protected]\"}";

　　此时用JSONObject：

　　　　

1 String str = "{\"name\":\"zhangsan\",\"password\":\"zhangsan123\",\"email\":\"[email protected]\"}";
2 JSONObject json = JSONObject.fromObject(str);
3 System.out.println(json.getString("name"));

 

 

 

 

二、

　  String jsonString = "[{\"name\":\"zhangsan\",\"password\":\"zhangsan123\",\"email\":\"[email protected]\"}"

　　　　　　　　　　　　+ ",{\"name\":\"lisi\",\"password\":\"lisi123\",\"email\":\"[email protected]\"}]";

　　此时用JSONArray:

 

1 String jsonString = "[{\"name\":\"zhangsan\",\"password\":\"zhangsan123\",\"email\":\"[email protected]\"}"
2     + ",{\"name\":\"lisi\",\"password\":\"lisi123\",\"email\":\"[email protected]\"}]";
3 JSONArray jsonArray = JSONArray.fromObject(jsonString);
4 for(int i = 0 ;i < jsonArray.size() ; i++){
5     System.out.println("name = "+jsonArray.getJSONObject(i).getString("name"));
6     System.out.println("password = "+jsonArray.getJSONObject(i).getString("password"));
7     System.out.println("email = "+jsonArray.getJSONObject(i).getString("email"));
8 }

 

 

　　　　

两个的输出结果为：

zhangsan
=========================================
name = zhangsan
password = zhangsan123
email = [e-mail]
name = lisi
password = lisi123
email = [email protected]