JavaScript中对象数组 作业升级版

Posted 2020-11-01 夏天里的Jasmine

var BaiduUsers = [], WechatUsers = [];
var User = function(id, name, phone, gender, age, salary) {
this.id = id;
this.name = name;
this.phone = phone;
this.gender = gender;
this.age = age;
this.salary = salary;
};
User.create = function(id, name, phone, gender, age, salary) {
    return new User(id, name, phone, gender, age, salary);
};
BaiduUsers.push(User.create(1, ‘tommy‘, ‘1111‘,‘male‘, 18, 10000));
BaiduUsers.push(User.create(2, ‘jerry‘, ‘2222‘,‘male‘, 28, 10000));
BaiduUsers.push(User.create(3, ‘raobin‘,‘3333‘,‘female‘, 14, 1200));
BaiduUsers.push(User.create(4, ‘binbin‘,‘4444‘,‘male‘, 23, 9800));
BaiduUsers.push(User.create(5, ‘yuyu‘,‘5555‘,‘female‘, 22, 10000));
WechatUsers.push(User.create(1, ‘yuyu‘, ‘1111‘,‘male‘, 20, 40000));
WechatUsers.push(User.create(2, ‘allen‘, ‘6666‘,‘male‘, 34, 15800));
WechatUsers.push(User.create(3, ‘raobin‘,‘3333‘,‘female‘,16, 2300));
WechatUsers.push(User.create(4, ‘harvey‘,‘7777‘,‘male‘,30, 29800));
WechatUsers.push(User.create(5, ‘yuyu‘,  ‘8888‘,‘female‘,27, 7000));
 
//Step1:将被收购公司的人员，手机号存在于原公司的，进行合并工资并且删除
for (var i = 0; i < BaiduUsers.length; i++) {
for (var y = 0; y< WechatUsers.length; y++) {
if (BaiduUsers[i].phone==WechatUsers[y].phone)
{
WechatUsers[y].oldsalary=WechatUsers[y].salary;
WechatUsers[y].salary=WechatUsers[y].salary+BaiduUsers[i].salary;
BaiduUsers.splice(i,1)
}
}
}
//Step2:将被收购公司剩余人员工资乘以1.2,并且改变ID
var len=WechatUsers.length;
for (var i = 0; i < BaiduUsers.length; i++) {
BaiduUsers[i].oldsalary =BaiduUsers[i].salary;
BaiduUsers[i].salary = BaiduUsers[i].salary*1.2;
BaiduUsers[i].id = WechatUsers.length+1+i;
}
//Step3:定义一个新对象数组，连接上述两个数组
var Aftereat=WechatUsers.concat(BaiduUsers)
 
 
//Step4:计算收购之后的最高工资，最低工资，平均工资，male的平均工资，female的平均工资等
//

var avgall=Aftereat.map(function(value){

return value.salary;

}).reduce(function(previous,current,index,array){
return previous+cirrent;})

var arrsalary =[]
for(var i=0;i<Aftereat.length;i++){
arrsalary.push(Aftereat[i].salary)
}
 
 
var malesalary =[]
var femalesalary =[]
for(var i=0;i<Aftereat.length;i++){
if(Aftereat[i].gender==‘male‘){
malesalary.push(Aftereat[i].salary)
}else if (Aftereat[i].gender==‘female‘){
femalesalary.push(Aftereat[i].salary)
}else{console.log("性别无法识别亲");
}
}
 
 
var avgmale
var avgfemale
 
function avg(dataIntArr) {
        var avg=0;
        for(var i=0;i<dataIntArr.length;i++){
 
            avg+=parseFloat(dataIntArr[i]);
        }
        return avg/dataIntArr.length;
    }
     
     
avg(arrsalary)
avg(malesalary)
avg(femalesalary)
 
 
var topsalary=0
var summarysalary=0
var bottomsalary=99999999999
for(var i=0;i<arrsalary.length;i++){
summarysalary +=arrsalary[i];
if(arrsalary[i]>topsalary)
{topsalary=arrsalary[i]}
if(arrsalary[i]<bottomsalary)
{bottomsalary=arrsalary[i]}
}
 
var avgall=summarysalary/arrsalary.length
console.log(bottomsalary);
console.log(topsalary);
console.log(summarysalary);
console.log(avgall);
console.log(avg(arrsalary));//-------全员工平均工资
console.log(avg(malesalary));//-------男员工平均工资
console.log(avg(femalesalary));//-------女员工平均工资
 
 
//Step5:找出收购后工资高于8000的员工姓名和电话号码，按薪水从高到低排序
function sortBy(filed)
{
return function(a,b){
return b[filed]-a[filed]
}
}
Aftereat.sort(sortBy("salary"))
 
 
 
var arrmorethan8000 = new Array();
var UserArray = function(name, phone) {
 this.name = name;
 this.phone = phone;
 };
UserArray.add = function(name, phone) {
 return new UserArray(name, phone);
};
 
for (var i = 0; i < Aftereat.length; i++) {
if (Aftereat[i].salary>8000){
arrmorethan8000.push(
UserArray.add(Aftereat[i].name,Aftereat[i].phone)
)
}
}
arrmorethan8000
 
var MMM=Aftereat
 
//Step6:找出收购前后工资涨幅最高的员工姓名和电话号码，以及涨幅的百分比
for (var i = 0; i < MMM.length; i++) {
if(MMM[i].oldsalary!=undefined)
{
MMM[i].salaryrise=MMM[i].salary -MMM[i].oldsalary ;
MMM[i].percentrise=MMM[i].salaryrise/MMM[i].oldsalary*100;
}else{MMM.splice(i,1)}
}
 
 
function sortBy(filed)
{
return function(a,b){
return b[filed]-a[filed]
}
}
MMM.sort(sortBy("percentrise"))
 
//Step7:找出收购后重名最多的三个姓名，统一出他们的平均年龄
var tempObj = {};
var LLL=Aftereat
for(var i=LLL.length-1; i>=0; i--){
if(tempObj[LLL[i].name]){ // 得到元素出现的次数，并组成obj
        tempObj[LLL[i].name] = tempObj[LLL[i].name]+1;
    }else{
        tempObj[LLL[i].name] = 1;
    }
}
 
var mostVal;
for(var key in tempObj){ // 从对象中得到数组中出现最多的元素
    if(!mostVal){
        mostVal = key;
    }else if(tempObj[mostVal]<tempObj[key]){
        mostVal = key;
    }
}
delete tempObj.mostVal
 
var name=[]
for (var i = 0; i < Aftereat.length; i++) {
if(Aftereat[i].name==mostVal)
{name.push(Aftereat[i].age)}
}
 
 
avg(name)