直接用HTTP返回JSON到浏览器

Posted 2020-10-26 bbchao

spring mvc 配置返回json需要两个重要的bean 

ContentNegotiatingViewResolver

MappingJackson2JsonView

具体看代码

<bean id="contentNegotiationManager" class="org.springframework.web.accept.ContentNegotiationManagerFactoryBean">
        <property name="mediaTypes">
            <value>
                html=text/html
                json=application/json
                xml=application/xml
            </value>
        </property>
        <property name="defaultContentType" value="text/html"/>
    </bean>

    <!-- ContentNegotiatingViewResolver视图解析器,利用他就可以配置多种返回值 -->
    <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver">
        <property name="order" value="0"/>
        <property name="contentNegotiationManager" ref="contentNegotiationManager"/>

        <property name="viewResolvers">
            <list>
                <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
                    <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
                    <property name="prefix" value="/WEB-INF/jsp/"/>
                    <property name="suffix" value=".jsp"/>
                </bean>
            </list>
        </property>

        <property name="defaultViews">
            <list>
                <bean  class="org.springframework.web.servlet.view.json.MappingJackson2JsonView">
                    <property  name="extractValueFromSingleKeyModel" value="true" />
                </bean>
                <bean  class="org.springframework.web.servlet.view.xml.MarshallingView">
                    <property name="marshaller">
                        <bean  class="org.springframework.oxm.xstream.XStreamMarshaller" />
                    </property>
                </bean>
            </list>
        </property>
    </bean>

    <bean id="multipartResolver" class="org.springframework.web.multipart.support.StandardServletMultipartResolver"/>