编写一个类Person，为Person类定义年龄、姓名两个属性

Posted 2023-03-13

编写一个类Person，为Person类定义年龄、姓名两个属性，并且定义一个SayHello方法，方法执行时输出“我是***我的年龄是***”；定义一个Chinese类从Person类继承。求解答，谢谢！

参考技术A #include<iostream.h>

class Person

public:
Person(char *name="",int age=0)

m_name=name;
m_age=age;

void SayHello()

cout<<"我叫"<<m_name<<","<<"年龄"<<m_age<<endl;

private:
char * m_name;
int m_age;
;

class Chinese :public Person

public:
Chinese(char * nation="中国人",char *name=" ",int age=0):Person(name,age)

m_nation=nation;

void SayHello()

cout<<"我是"<<m_nation<<endl;
Person::SayHello();

private:
char * m_nation;
;
void main()


参考技术B class Person
private:
int age;
string name;
public:
void SayHello();
;

void Person::SayHello()

cout<<"我是""<<name;
cout<<"我的年龄是"<<age;


class Chinese:Person