customer_details	details
customer_id	Int, 1 - 500
first_name	string
last_name	string
email	string, such as willddy@gmail.com
gender	string, Male or female
address	string
country	string
language	string
job	string, job title/position
credit_type	string, credit card type, such as visa
credit_no	string, credit card number

Transaction表

transaction_details	details
transaction_id	Int, 1 - 1000
customer_id	Int, 1 - 500
store_id	Int, 1 - 5
price	decimal, such as 5.08
product	string, things bought
date	string, when to purchase
time	string, what time to purchase

Store表

store_details	details
store_id	Int, 1 - 5
store_name	string
employee_number	Int, 在store有多少employee

Review表

store_review	details
stransaction_id	Int, 1 - 8000
store_id	Int, 1 - 5
review_store	Int, 1 - 5

上传数据

创建目录用于存放数据

%sh
hdfs dfs -mkdir -p /shopping/data/customer
hdfs dfs -mkdir -p /shopping/data/store
hdfs dfs -mkdir -p /shopping/data/review
hdfs dfs -mkdir -p /shopping/data/transaction

把本地文件上传到HDFS上

%sh
cd /opt/stufile/storetransaction
ls -al

hdfs dfs -put ./customer_details.csv /shopping/data/customer
hdfs dfs -put ./store_details.csv /shopping/data/store
hdfs dfs -put ./store_review.csv /shopping/data/review
hdfs dfs -put ./transaction_details.csv /shopping/data/transaction

创建外部表

创建数据库

%hive
-- 如果存在此表则删除
drop database if exists shopping cascade;
--创建数据库
create database if not exists shopping;

创建表

%hive
create external table if not exists ext_customer_detail
(
    customer_id string,
    first_name  string,
    last_name   string,
    email       string,
    gender      string,
    address     string,
    country     string,
    language    string,
    job         string,
    credit_type string,
    credit_no   string
)
    row format serde 'org.apache.hadoop.hive.serde2.OpenCSVSerde'
    location '/shopping/data/customer'
    tblproperties ('skip.header.line.count' = '1');

create external table if not exists ext_transaction_details
(
    transaction_id string,
    customer_id    string,
    store_id       string,
    price          decimal(8, 2),
    product        string,
    purchase_date  string,
    purchase_time  string
) row format serde 'org.apache.hadoop.hive.serde2.OpenCSVSerde'
    location '/shopping/data/transaction'
    tblproperties ('skip.header.line.count' = '1');

drop table ext_store_details;
create external table if not exists ext_store_details
(
    store_id        string,
    store_name      string,
    employee_number string

) row format serde 'org.apache.hadoop.hive.serde2.OpenCSVSerde'
    location '/shopping/data/store'
    tblproperties ('skip.header.line.count' = '1');

drop table ext_store_review;
create external table if not exists ext_store_review
(
    store_id       string,
    transaction_id string,
    review_score   string
) row format serde 'org.apache.hadoop.hive.serde2.OpenCSVSerde'
    location '/shopping/data/review'
    tblproperties ('skip.header.line.count' = '1');

TIP:

OpenCSVSerde 默认的分隔符 (separator)、quote 以及逃逸字符（escape characters ）分别为、" 以及 '

如果我们查看表结构的时候，我们会发现如果 row format serde 为 org.apache.hadoop.hive.serde2.OpenCSVSerde，不管你建表的时候指定字段是什么类型，其显示的都是 string 类型

tblproperties ('skip.header.line.count' = '1');从外部表导入数据跳过（忽略）首行。

数据清洗

对transaction_details中的重复数据生成新ID

%hive
use shopping;
with basetb as (
    select row_number() over (partition by transaction_id order by transaction_id) as rn
         , transaction_id
         , customer_id
         , store_id
         , price
         , product
         , purchase_date
         , purchase_time
         , substr(purchase_date, 0, 7)                                             as purchase_month
    from ext_transaction_details),
     basetb2 as (
         select `if`(rn = 1, transaction_id, concat(transaction_id, '_fix', rn)) transaction_id
              , customer_id
              , store_id
              , price
              , product
              , purchase_date
              , purchase_time
              , purchase_month
         from basetb)
select *
from basetb2
where transaction_id like '%fix%';

因为查询的数据比较多，显示不全所有要在后面加一个查询

过滤掉store_review中没有评分的数据

查出有评分的数据

%hive
use shopping;
create view if not exists vm_store_review as
select *
from ext_store_review
where review_score <> '';


select * from vm_store_review;

找出PII (personal information identification‘个人信息识别’) 数据进行加密

%hive
use shopping;
drop view customer_detail;
create view vm_customer_details as
select 
customer_id,first_name,unbase64(last_name)as last_name,unbase64(email) as email,
gender,unbase64(address) as address,
unbase64(concat(unbase64(credit_no),'hello')) as credit_no --二次加密
from ext_customer_details;

重新组织transaction数据按照日期YYYY-MM（按月）做分区

%hive
use shopping;
set hive.exec.dynamic.partition.mode=nonstrict;
with basetb as (
    select row_number() over (partition by transaction_id order by transaction_id) as rn
         , transaction_id
         , customer_id
         , store_id
         , price
         , product
         , purchase_date
         , purchase_time
         , substr(purchase_date, 0, 7)                                             as purchase_month
    from ext_transaction_details)
insert overwrite table transaction_details partition (purchase_month)
select `if`(rn = 1, transaction_id, concat(transaction_id, '_fix', rn)) transaction_id
     , customer_id
     , store_id
     , price
     , product
     , purchase_date
     , purchase_time
     , purchase_month
from basetb;


show partitions transaction_details;

Customer分析

1.找出顾客最常用的信用卡

%hive
use shopping;
select credit_type, max(credit_type) counts
from ext_customer_details
group by credit_type
order by counts desc;

2.找出户客资料中排名前五的职位名称

select job, count(job) counts
from ext_customer_details
group by job
order by counts desc
limit 5;

3.在美国女性最常用的信用卡

%hive
use shopping;
select credit_type, count(credit_type) counts
from ext_customer_details
where gender = 'Female' and country='United States'
group by credit_type
order by counts desc;

4.按性别和国家进行客户统计

%hive
use shopping;
select country, gender,count(customer_id)
from ext_customer_details
group by gender, country;

Transaction

1.计算每月总收入

%hive
use shopping;
select substr(purchase_date,0,7) month,round(sum(price),2) sum
from ext_transaction_details
group by substr(purchase_date,0,7);

2.计算每个季度的总收入

with basetb as (
    select concat_ws('-', cast(year(purchase_date) as string),
                     cast(quarter(purchase_date) as string)) as year_quarter,
           price
    from transaction_details)
select year_quarter ,sum(price) sumMoney from basetb group by year_quarter;

3.按年计算总收入

%hive
use shopping;
select year(purchase_date) years , round(sum(price),2) sum
from ext_transaction_details
group by year(purchase_date);

4.按工作日计算总收入

%hive
use shopping;
with basetb as (
    select `dayofweek`(purchase_date) weekday, price
    from transaction_details)
select case
           when (weekday - 1) = 1 then '星期一'
           when (weekday - 1) = 2 then '星期二'
           when (weekday - 1) = 3 then '星期三'
           when (weekday - 1) = 4 then '星期四'
           when (weekday - 1) = 5 then '星期五'
           end as weekday,
       sum(price) sum
from basetb
group by weekday
having weekday between 2 and 6;

5.按时间段计算总收入(需要清理数据)

%hive
use shopping;

with basetb1 as (
    select price,
           purchase_time,
           case
               when purchase_time like '%AM' then split(purchase_time, '\\\\s+')[0]
               when purchase_time like '%PM' then concat_ws(':',cast(`if`(
                                                                    (cast(split(purchase_time, ':')[0] as int) + 12) == 24,0,          (cast(split(purchase_time, ':')[0] as int) + 12)) as string)
                   , split(split(purchase_time, ':')[1], '\\\\s+')[0])
               else purchase_time
               end time_format
    from transaction_details),
     basetb2 as (select price,
                        purchase_time,
                        (cast(split(time_format, ':')[0] as decimal(4, 2)) +
                         cast(split(time_format, ':')[1] as decimal(4, 2)) / 60) purchase_time_num
                 from basetb1),
     basetb3 as (select price,
                        purchase_time,
                        `if`(purchase_time_num > 5 and purchase_time_num <= 8, 'early morning',
                        `if`(purchase_time_num > 8 and purchase_time_num <= 11, ' morning',
                        `if`(purchase_time_num > 11 and purchase_time_num <= 13, 'noon',
                        `if`(purchase_time_num > 13 and purchase_time_num <= 18, 'afternoon',
                        `if`(purchase_time_num > 18 and purchase_time_num <= 22, 'evening','night'))))) as time_bucket
                 from basetb2)
select time_bucket, sum(price) sum
from basetb3
group by time_bucket;

6.按时间段计算平均消费

%hive
use shopping;

with basetb1 as (
    select price,
           purchase_time,
           case
               when purchase_time like '%AM' then split(purchase_time, '\\\\s+')[0]
               when purchase_time like '%PM' then concat_ws(':',cast(`if`(
                                                                    (cast(split(purchase_time, ':')[0] as int) + 12) == 24,0,          (cast(split(purchase_time, ':')[0] as int) + 12)) as string)
                   , split(split(purchase_time, ':')[1], '\\\\s+')[0])
               else purchase_time
               end time_format
    from transaction_details),
     basetb2 as (select price,
                        purchase_time,
                        (cast(split(time_format, ':')[0] as decimal(4, 2)) +
                         cast(split(time_format, ':')[1] as decimal(4, 2)) / 60) purchase_time_num
                 from basetb1),
     basetb3 as (select price,
                        purchase_time,
                        `if`(purchase_time_num > 5 and purchase_time_num <= 8, 'early morning',
                        `if`(purchase_time_num > 8 and purchase_time_num <= 11, ' morning',
                        `if`(purchase_time_num > 11 and purchase_time_num <= 13, 'noon',
                        `if`(purchase_time_num > 13 and purchase_time_num <= 18, 'afternoon',
                        `if`(purchase_time_num > 18 and purchase_time_num <= 22, 'evening','night'))))) as time_bucket
                 from basetb2)
select time_bucket, avg(price) avg
from basetb3
group by time_bucket;

7.按工作日计算平均消费

%hive
use shopping;
with basetb as (
    select `dayofweek`(purchase_date) weekday, price
    from transaction_details)
select case
           when (weekday - 1) = 1 then '星期一'
           when (weekday - 1) = 2 then '星期二'
           when (weekday - 1) = 3 then '星期三'
           when (weekday - 1) = 4 then '星期四'
           when (weekday - 1) = 5 then '星期五'
           end weekday,
    avg(price) avg
from basetb
group by weekday
having weekday between 2 and 6;

8.计算年、月、日的交易总数

%hive
use shopping;
select distinct purchase_date,
       purchase_month,
       year(purchase_date),
       count(1) over (partition by year(purchase_date))                                         years,
       count(1) over (partition by year(purchase_date),month(purchase_date))                    months,
       count(1) over (partition by year(purchase_date),month(purchase_date),day(purchase_date)) days
from transaction_details;

9.找出交易量最大的10个客户

%hive
use shopping;
select
customer_id,count(1) as num
from transaction_details
group by customer_id
order by num desc
limit 10

10.找出消费最多的前10位顾客

%hive
use shopping;
select customer_id,
       sum(price) as sum
from transaction_details
group by customer_id
order by sum desc
limit 10

11.计该期间交易数量最少的用户

use shopping;
select customer_id, count(transaction_id)
from transaction_details
group by customer_id
order by count(transaction_id)
limit 1;

12.算每个季度的独立客户总数

%hive
use shopping;
with basetb as (
    select distinct concat_ws('-', cast(year(purchase_date) as string),
                     cast(quarter(purchase_date) as string)) as year_quarter,
           customer_id
    from transaction_details)
select  year_quarter, count(customer_id) counts
from basetb
group by year_quarter;

13.算每周的独立客户总数

%hive
use shopping;
with basetb as (
    select distinct concat(cast(year(purchase_date) as string), '-', cast(weekofyear(purchase_date)as string)) weeks,
                    customer_id
    from transaction_details)
select weeks, count(customer_id) counts
from basetb
group by weeks;

14.算整个活动客户平均花费的最大值

%hive
use shopping;
select customer_id,avg(price) avgs
from transaction_details
group by customer_id
order by avgs desc
limit 1;

15.计每月花费最多的客户

%hive
use shopping;
with basetb as (
    select purchase_month,
           customer_id,
           sum(price) sum_price
    from transaction_details
    group by purchase_month, customer_id),
     basetb2 as (
         select purchase_month,
                customer_id,
                sum_price,
                row_number() over (partition by purchase_month order by sum_price desc ) rn
         from basetb)
select purchase_month, customer_id, sum_price
from basetb2
where rn = 1;

16.计每月访问次数最多的客户

%hive
use shopping;
with basetb as (
    select purchase_month,
           customer_id,
           count(customer_id) counts
    from transaction_details
    group by purchase_month, customer_id),
     basetb2 as (
         select purchase_month,
                customer_id,
                counts,
                row_number() over (partition by purchase_month order by counts desc ) rn
         from basetb)
select purchase_month, customer_id, counts
from basetb2
where rn = 1;

17.总价找出最受欢迎的5种产品

select product,sum(price) sum
from transaction_details
group by product
order by sum desc
limit 5;

18.据购买频率找出最畅销的5种产品

select product,
count(1) counts
from transaction_details
group by product
order by counts desc
limit 5;

19.据客户数量找出最受欢迎的5种产品

select product,
count(distinct customer_id) counts
from transaction_details
group by product
order by counts desc
limit 5

Store分析

1.按客流量找出最受欢迎的商店

%hive
use shopping;
select store_name, count(distinct customer_id) counts
from transaction_details td
         join ext_store_details esd on td.store_id = esd.store_id
group by store_name
order by counts desc;

2.根据顾客消费价格找出最受欢迎的商店

%hive
use shopping;
select store_name, sum(price) sums
from transaction_details td
         join ext_store_details esd on td.store_id = esd.store_id
group by store_name
order by sums desc;

3.根据顾客交易情况找出最受欢迎的商店

%hive
use shopping;
select store_name, count(td.store_id) counts
from transaction_details td
         join ext_store_details esd on td.store_id = esd.store_id
group by store_name
order by counts desc;

4.根据商店和唯一的顾客id获取最受欢迎的产品

%hive
use shopping;
with basetb as (
    select store_id, product, count(distinct customer_id) counts
    from transaction_details
    group by store_id, product),
     basetb2 as (
         select store_id,
                product,
                counts,
                rank() over (partition by store_id order by counts desc ) as rn
         from basetb)
select store_name, product, counts
from basetb2 tb2
         join ext_store_details esd on tb2.store_id = esd.store_id
where rn = 1;

5.获取每个商店的员工与顾客比

%hive
use shopping;
with t1 as (select count(1) c1, store_id
            from transaction_details td
            group by td.store_id)
select t1.store_id,
       esd.store_name,
       concat(substring(cast(esd.employee_number / t1.c1 as decimal(9, 8)) * 100.0, 0, 4), '%') proportion
from t1
         join ext_store_details esd on t1.store_id = esd.store_id;

6.按年和月计算每家店的收入

%hive
use shopping;
select distinct *
from (
         select store_id,
                year(purchase_date)                                                     year,
                sum(price) over (partition by year(purchase_date))                      sum_year,
                month(purchase_date)                                                    month,
                sum(price) over (partition by year(purchase_date),month(purchase_date)) sum_month
         from transaction_details
     ) tb;

7.按店铺制作总收益饼图

%hive
use shopping;
select store_id,sum(price)
from transaction_details
group by store_id

8.找出每个商店最繁忙的时间段

%hive
use shopping;
with basetb1 as (
    select store_id,
           customer_id,
           purchase_time,
           case
               when purchase_time like '%AM' then split(purchase_time, '\\\\s+')[0]
               when purchase_time like '%PM' then concat_ws(':',
                                                            cast(`if`(
                                                                    (cast(split(purchase_time, ':')[0] as int) + 12) == 24,
                                                                    0,
                                                                    (cast(split(purchase_time, ':')[0] as int) + 12)) as string)
                   , split(split(purchase_time, ':')[1], '\\\\s+')[0])
               else purchase_time
               end time_format
    from transaction_details),
     basetb2 as (select store_id,
                        customer_id,
                        purchase_time,
                        (cast(split(time_format, ':')[0] as decimal(4, 2)) +
                         cast(split(time_format, ':')[1] as decimal(4, 2)) / 60) purchase_time_num
                 from basetb1),
     basetb3 as (select store_id,
                        customer_id,
                        purchase_time,
                        `if`(purchase_time_num > 5 and purchase_time_num <= 8, 'early morning',
                             `if`(purchase_time_num > 8 and purchase_time_num <= 11, 'morning',
                                  `if`(purchase_time_num > 11 and purchase_time_num <= 13, 'noon',
                                       `if`(purchase_time_num > 13 and purchase_time_num <= 18, 'afternoon',
                                            `if`(purchase_time_num > 18 and purchase_time_num <= 22, 'evening',
                                                 'night'))))) as time_bucket
                 from basetb2)
select esd.store_name,
       tb3.time_bucket,
       count(customer_id) counts
from basetb3 tb3
         join ext_store_details esd on tb3.store_id = esd.store_id
group by esd.store_name, time_bucket;

9.找出每家店的忠实顾客

购买次数大于5，认为他是忠实粉丝

%hive
use shopping;
select *
from (
         select store_id, customer_id, count(1) counts
         from transaction_details
         group by store_id, customer_id) tb
where tb.counts > 5;

10.根据每位员工的最高收入找出明星商店

%hive
use shopping;
with base as
         (
             select store_id, sum(price) s
             from transaction_details
             group by store_id
         )
select base.store_id,
       base.s / store.employee_number en
from base
         join ext_store_details store
              on base.store_id = store.store_id
order by en desc
limit 1;

Review分析

1.在ext_store_review中找出存在冲突的交易映射关系

%hive
use shopping;
with basetb as (
    select row_number() over (partition by transaction_id) as row_number1, * from vm_store_review
)
select row_number1, a.transaction_id, a.store_id, b.store_id, a.review_score, b.review_score
from basetb a
         join vm_store_review b on a.transaction_id = b.transaction_id
where row_number1 > 1;

2.了解客户评价的覆盖率

%hive
use shopping;
with t1 as (
    select count(1) c1
    from ext_store_review
    where review_score <> ''
),
     t2 as (
         select count(1) c2
         from ext_store_review
         where review_score = ''
     )
select concat(cast((c1 - c2) / c1 * 100 as decimal(4, 2)), '%')  Coverage
from t1 join t2;

3.根据评分了解客户的分布情况

%hive
use shopping;
select concat(round(sum(case review_score when '1' then 1 else 0 end) / count(*) * 100, 2), '%') as one_score,
       concat(round(sum(case review_score when '2' then 1 else 0 end) / count(*) * 100, 2), '%') as two_score,
       concat(round(sum(case review_score when '3' then 1 else 0 end) / count(*) * 100, 2), '%') as three_score,
       concat(round(sum(case review_score when '4' then 1 else 0 end) / count(*) * 100, 2), '%') as four_score,
       concat(round(sum(case review_score when '5' then 1 else 0 end) / count(*) * 100, 2), '%') as five_score
from ext_store_review;

4.根据交易了解客户的分布情况

根据总金额

%hive
use shopping;
select country,
       sum(price) sum_price
from transaction_details td
         join ext_customer_details cd on td.customer_id = cd.customer_id
group by cd.country;

5.客户给出的最佳评价是否总是同一家门店

%hive
use shopping;
select store_id, customer_id, count(customer_id) counts
from transaction_details td
         join ext_store_review esr
              on esr.transaction_id = td.transaction_id
where esr.review_score = 5
group by td.store_id, td.customer_id;

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