ajax问题

Posted 2020-09-20 九门提督琪琪

1.简单模板

　　success访问成功不等于返回数据成功

$.ajax({
    type:"get",
    data:freedata,
    dataType:"jsonp",
    url:url,
    success:function (data) {
        if (data.retcode == "00") {
            var item = data.freesort;
            numNow=data.luckytimes;
            $rule_number.text(numNow);
            var note=data.freecardname.replace(",","").replace(",","").replace(",","");
            rotateFn(item,note);
        } else {
            awardAlert(data.result);
        };

    },
    error:function () {
        awardAlert("网络超时，请稍后尝试",{bname:"取消"});
    }
})