JSON序列化，并解码成为 datagridview 的 datasource

Posted 2020-09-16 齐文宣

            // encode 
            List<clientState> clientList = new List<clientState>();
            for (int i = 0; i < 5; i++)
            {
                clientState cst = new clientState { clientConnectTime = DateTime.Now, clientRecv = 1, clienthandle = 2, clientIP = "127.0.0.1" };
                clientList.Add(cst);
            }
            string sReply = JsonConvert.SerializeObject(clientList);

            //decode 

            List<clientState> source1 = JsonConvert.DeserializeObject<List<clientState>>(sReply);
            var Dsource = new BindingSource();
            Dsource.DataSource = source1;
            dataGridView1.DataSource = Dsource;
            //dataGridView1.Invoke((Action)(() => dataGridView1.DataSource = Dsource));    如果在线程中，就这样写


/////////////////////////////////////////////////////////////////////////////////////////////////////        
        class clientState
        {
            public DateTime clientConnectTime { get; set; }
            public int clientRecv { get; set; }
            public int clienthandle { get; set; }
            public string clientIP { get; set; }
        }