easyui tree后台传json处理问题
Posted hzhh123
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一、tree json格式
[ { "id": 1, "text": "权限管理", "iconCls": "icon-feed", "checked": false, "attributes": { "url": "#123" }, "children": [ { "id": 2, "text": "用户管理", "iconCls": "icon-users", "checked": false, "attributes": { "url": null }, "state": null }, { "id": 3, "text": "角色管理", "iconCls": "icon-users", "checked": false, "attributes": { "url": null }, "children": [ { "id": 10, "text": "角色管理1", "iconCls": "icon-users", "checked": false, "attributes": { "url": null }, "state": null } ], "state": null }, { "id": 4, "text": "菜单管理", "iconCls": "icon-users", "checked": false, "attributes": { "url": "#222" }, "state": null, "children":[] //注意这里的state值设置很关键,若为父节点,state="open"|"close",若为叶子节点,只能为空 //否则出错,如图① } ] }, { "id": 5, "text": "系统模块", "iconCls": "icon-feed", "checked": false, "attributes": { "url": null }, "state": null }, { "id": 6, "text": "系统模块2", "iconCls": "icon-feed", "checked": false, "attributes": { "url": null } }, { "id": 7, "text": "系统模块3", "iconCls": "icon-feed", "checked": false, "attributes": { "url": null } }, { "id": 8, "text": "系统模块4", "iconCls": "icon-feed", "checked": false, "attributes": { "url": null } }, { "id": 9, "text": "系统模块5", "iconCls": "icon-feed", "checked": false, "attributes": { "url": null } } ]
如图①
正确的图是
二、tree加载方式
1、html格式
<ul id="tt" class="easyui-tree"> <li> <span>Folder</span> <ul> <li> <span>Sub Folder 1</span> <ul> <li> <span><a href="#">File 11</a></span> </li> <li> <span>File 12</span> </li> <li> <span>File 13</span> </li> </ul> </li> <li> <span>File 2</span> </li> <li> <span>File 3</span> </li> </ul> </li> <li> <span>File21</span> </li> </ul>
2、加载json文件,如tree_data.json,内容如上
<ul id="tt"></ul>
$(\'#tt\').tree({
url:\'tree_data.json\'
});
3、从后台数据库传json字符串值
①实体类
②tree json格式对应的实体类
③实体类Menu转化为TreeNode格式(tree json格式),进行递归调用返回树形菜单
import java.util.ArrayList;
import java.util.HashMap; import java.util.List; import java.util.Map; import sys.entity.Menu; public class TreeNodeUtil { public static List<TreeNode> tree(List<TreeNode>nodes,Integer id) { //递归转化为树形 List<TreeNode> treeNodes=new ArrayList<TreeNode>(); for(TreeNode treeNode : nodes) { TreeNode node=new TreeNode(); node.setId(treeNode.getId()); node.setText(treeNode.getText()); node.setAttributes(treeNode.getAttributes()); node.setIconCls(treeNode.getIconCls()); node.setState(treeNode.getState()); node.setPid(treeNode.getPid()); if(id==treeNode.getPid()){ node.setChildren(tree(nodes, node.getId())); treeNodes.add(node); } } return treeNodes; }
//转化为TreeNode节点 public static TreeNode toNode(Menu menu){ TreeNode node=new TreeNode(); node.setId(menu.getId()); node.setIconCls(menu.getIcon()); node.setPid(menu.getParentMenuId()); System.out.println(node.getPid()); node.setText(menu.getMenuName()); node.setState(menu.getState()); Map<String,Object>attributes=new HashMap<String,Object>(); attributes.put("url", menu.getUrl()); node.setAttributes(attributes); return node; } public static List<TreeNode>toListNode(List<Menu>menus){ List<TreeNode>nodes=new ArrayList<TreeNode>(); for(Menu menu:menus){ nodes.add(toNode(menu)); } return nodes; } }
④查询出需要的菜单记录,我这里是权限管理系统,一个角色对应多个菜单,通过角色id查询出菜单记录,一个用户有多个角色,所以多个角色对应的菜单可能有交集,这里采用rbac的白名单权限,获得最大的菜单权限。
@Override public List<Menu> getMenuByRoleId(Integer[] roleIds) { List<Menu>menus=new ArrayList<Menu>(); for(Integer roleId:roleIds){ List<Menu>menus1=menuMapper.selectByRoleId(roleId); for(Menu menu:menus1){ if(!menus.contains(menu)){ menus.add(menu); } } } return menus;
}
⑤controller层代码
@ResponseBody @RequestMapping(value="treeView") public List<TreeNode> treeView(@RequestParam("roleIds")String roleIdStr){ String param[]=roleIdStr.split(","); Integer[] roleIds=new Integer[param.length]; for(int i=0;i<param.length;i++){ roleIds[i]=Integer.parseInt(param[i]); } List<Menu>menus=menuService.getMenuByRoleId(roleIds); List<TreeNode>nodes=TreeNodeUtil.toListNode(menus); List<TreeNode>treeNodes=TreeNodeUtil.tree(nodes, 0); for(TreeNode node:nodes){ System.out.println(node.getIconCls()); System.out.println(node.getPid()); } return treeNodes; }
结果:
⑥数据库部分设计
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