Json

Posted 2020-09-04 John的救赎

1.在javascript中创建一个新的 JavaScript 变量，然后将 JSON 格式的数据字符串直接赋值给它：  

var  people=   {      "programmers":[  "firstName:","Brett","astName:","MclaughLin"........  "firstName:","Jason","astName:","Hunter"........  .........       ],      "authors":[  "firstName:","Isaac","astName:","Asimov"........  "firstName:","Tad","astName:","williams"........  .........       ]         .......      //如果不是结尾，每次增加一个需要用,号和下一个进行分隔

}

访问Json数据：      

 people.programmers[0].astName;//访问programmers列表的第一个条目的姓氏       

people.authors[1].astName                       // 访问authors列表的第二条目的姓氏        people.authors[3].astName          // Undefined. This refers to the fourth entry, and there isn‘t one  有点像访问访问数组时长度越界了

修改Json数据：

 people.programmers[0].astName="John";   //修改programmers列表的第一个条目的astName内容

Json转换成字符串: String newJSONtext = people.toJSONString();

对名为 myObject 的对象进行转换: String myObjectInJSON = myObject.toJSONString();