Kotlin书写动态代理method.invoke(iam, *args) must not be null

Posted 2023-02-07 csdn用户R

文章目录

• • 问题
  • • 1.动态代理使用Kotlin书写报错
    • • 描述
      • 思考
      • 解决

问题

1.动态代理使用Kotlin书写报错

描述

    Process: com.y.hookdemo, PID: 24014
    java.lang.IllegalArgumentException: method android.app.IActivityManager$Stub$Proxy.getActivityDisplayId argument 1 has type android.os.IBinder, got java.lang.Object[]
        at java.lang.reflect.Method.invoke(Native Method)
        at com.y.hookdemo.HookUtil$HookInvocationHandler.invoke(HookUtil.kt:121)

• kotlin书写：

    private class HookInvocationHandler(private val iam: Any): InvocationHandler 

        @Throws(Throwable::class)
        override fun invoke(proxy: Any, method: Method, args: Array<Any>): Any 
            if (method.name.contains("startActivity")) 
                Log.e("Hook", "IActivityManager动态代理的invoke方法,伪装intent")
                for (i in args.indices) 
                    if (args[i] is Intent) 
                        val intent = args[i] as Intent
                        val proxyIntent = Intent(mContext, ProxyActivity::class.java)
                        proxyIntent.putExtra("intent", intent)
                        args[i] = proxyIntent
                        break
                    
                
            
            return method.invoke(iam, args)
        
    

报错在 return method.invoke(iam, args) 这一行，用java写正常执行

• java书写：

        private class HookInvocationHandler implements InvocationHandler 

        private Object iam;

        private HookInvocationHandler(Object iam) 
            this.iam = iam;
        

        @Override
        public Object invoke(Object proxy, Method method, Object[] args) throws Throwable 
            if (method.getName().contains("startActivity")) 
                Log.e("Hook", "IActivityManager动态代理的invoke方法,伪装intent");
                for (int i = 0; i < args.length; i++) 
                    if (args[i] instanceof Intent) 
                        Intent intent = (Intent) args[i];
                        Intent proxyIntent = new Intent(mContext, ProxyActivity.class);
                        proxyIntent.putExtra("intent", intent);
                        args[i] = proxyIntent;
                        break;
                    
                
            
            return method.invoke(iam, args);
        
    

将java通过as转为kotlin，这行变为

return method.invoke(iam, *args)

第二个参数变为*args,依旧报错

com.y.hookdemo E/AndroidRuntime: Error reporting crash
    java.lang.IllegalStateException: method.invoke(iam, *args) must not be null
        at com.y.hookdemo.HookUtil$HookInvocationHandler.invoke(HookUtil.kt:121)
        at java.lang.reflect.Proxy.invoke(Proxy.java:913)

思考

    @CallerSensitive
    // Android-changed: invoke(Object, Object...) implemented natively.
    @FastNative
    public native Object invoke(Object obj, Object... args)
            throws IllegalAccessException, IllegalArgumentException, InvocationTargetException;

反射api中Method的invoke方法接收可变长参数，在java中允许数组赋值给可变长参数Object… args，Kotlin中，数组是array，可变长参数类型是vararg，类型不一致，所以method.invoke(iam, args),是两个参数，第二个参数是数组，实际方法需要多个参数，第二个参数是IBinder，所以报第一个错。
Kotlin中数组转为可变长参数，是通过前面加*，所以as把java转为kotlin后，变为method.invoke(iam, *args),参数正确，但依旧报第二个错.

???

解决

解决毛，谷歌吹个毛的java和kotlin可以一起用，改用java写了

kotlin书写时，返回值是Any，方法可能是没有返回值的，所以修改为Any？，然后修改

private class HookInvocationHandler(private val iam: Any): InvocationHandler 

        @Throws(Throwable::class)
        override fun invoke(proxy: Any, method: Method, args: Array<Any>): Any? 
            if (method.name.contains("startActivity")) 
                Log.e("Hook", "IActivityManager动态代理的invoke方法,伪装intent")
                for (i in args.indices) 
                    if (args[i] is Intent) 
                        val intent = args[i] as Intent
                        val proxyIntent = Intent(mContext, ProxyActivity::class.java)
                        proxyIntent.putExtra("intent", intent)
                        args[i] = proxyIntent
                        break
                    
                
            
            val res = method.invoke(iam, *args)
            Log.e("------a1:$method.name",args.size.toString())
            Log.e("res = ",res?.toString() + "--")
            Log.e("returnType:",method.genericReturnType.typeName)
            return if("void" == method.genericReturnType.typeName) Unit else res
        
    

正常运行

• 新的问题
  java书写时返回值为Object，执行没有返回值的method时，为什么可以