如何在Java中使用正则表达式将“：abc，cde t”替换为“，abc | cde”？

Posted 2021-03-27

我有一个像下面的字符串列表:(没有引号）

"<someother string without :>:abc	<some other string without 	>"
"<someother string without :>:abc,cde	<some other string without 	>"
"<someother string without :>:abc,efg,cde	<some other string without 	>"
"<someother string without :>:abc,cde	<some other string without 	>"

想将它们转换为：

"<someother string without :>|abc	<some other string without 	>"
"<someother string without :>|abc|cde	<some other string without 	>"
"<someother string without :>|abc|efg|cde	<some other string without 	>"
"<someother string without :>|abc|cde	<some other string without 	>"

我想知道它是否可行？

谢谢

答案

不要认为你可以用正则表达式来做这件事，除非你多次应用它。你可以这样做：

public static String convert(String s) {
    int start = s.indexOf(':') + 1;
    int end = s.indexOf('	', start);

    return s.substring(0, start)
            + s.substring(start, end).replaceAll(",", "|")
            + s.substring(end, s.length());
}

另一答案

试试这个：

public class T28Regex {
public static void main(String[] args) {
    String[] strings = { "<someother string without *>:abc	<some other string without 	>",
            "<someother string without *>:abc,cde	<some other string without 	>",
            "<someother string without *>:abc,efg,cde	<some other string without 	>",
            "<someother string without *>:abc,cde	<some other string without 	>" };

    for (String s : strings) {
        System.out.println(s.substring(0, s.indexOf(":")) + "|"
                + s.substring(s.indexOf(":") + 1, s.indexOf("	", s.indexOf(":"))).replaceAll(",", "|")
                + s.substring(s.indexOf("	", s.indexOf(":"))));
    }
}
}

另一答案

试试这个

function Replace_(str ) {
  var patt = /(:)((([w]*(,)?)){2,})(\t<)/gi;
  var res = str.replace(patt, function($1,$2,$3){
  return $1.replace(/,/g, "|").replace(":", "|");
  });
return res;
}

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