SpringBoot整合MybatisPlus有关条件构造器的相关查询方法

Posted 2021-03-19 社会大哥

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最近在学习mybatisPlus时总结了一些常用的有关条件构造器的查询方法，以此做下记录，方便学习使用！

eq: 等于 =

例子：eq("name", "老王")--->name = \'老王\'

ne: 不等于 <>

例子：ne("name", "老王")--->name <> \'老王\'

gt: 大于 >

例子：gt("age", 18)--->age > 18

ge: 大于等于 >=

例子：ge("age", 18)--->age >= 18

lt: 小于 <

例子：lt("age", 18)--->age < 18

le: 小于等于 <=

例子：le("age", 18)--->age <= 18

between: 值 1 AND 值 2

例子：between("age", 18, 30)--->age between 18 and 30

notBetween: Not BETWEEN 值 1 AND 值 2

例子：notBetween("age", 18, 30)--->age not between 18 and 30

like: like\'%值%\'

例子：like("name", "王")--->name like \'%王%\'

notLike: NOT LIKE \'%值%\'

例子：notLike("name", "王")--->name not like \'%王%\'

likeLeft: Like\'%值\'

例子：likeLeft("name", "王")--->name like \'%王\'

likeRight: LIKE\'值%\'

例子：likeRight("name", "王")--->name like \'王%\'

isNull: 字段 IS NULL

例子：isNull("name")--->name is null

isNotNull:字段 IS NOT NULL

例子：isNotNull("name")--->name is not null

in: 字段IN(value.get(0),value.get(1),...)

例子：in("age",{1,2,3})--->age in (1,2,3)

     字段 IN (v0, v1, ...)

例子：in("age", 1, 2, 3)--->age in (1,2,3)

notIn: 字段 IN (value.get(0), value.get(1), ...)

例子：notIn("age",{1,2,3})--->age not in (1,2,3)

           字段 NOT IN (v0, v1, ...)

例子：notIn("age", 1, 2, 3)--->age not in (1,2,3)

inSql: 字段 IN（SQL语句）

例子1：inSql("age", "1,2,3,4,5,6")--->age in (1,2,3,4,5,6)

例子2：inSql("id", "select id from table where id < 3")--->id in (select id from  table where id < 3)

notInSql: 字段NOT IN (sql语句)

例子1：notInSql("age", "1,2,3,4,5,6")--->age not in (1,2,3,4,5,6)

例子2：notInSql("id", "select id from table where id < 3")--->age not in (select id from table where id < 3)

分组：GROUP BY 字段，...

例子：groupBy("id", "name")--->group by id,name

升序: ORDER BY 字段，...ASC

例子：orderByAsc("id", "name")--->order by id ASC,name ASC

降序：ORDER BY 字段，...DESC

例子：orderByDesc("id", "name")--->order by id DESC,name DESC

排序：OREDR BY 字段，...

例子：orderBy(true, true, "id", "name")--->order by id ASC,name ASC

聚合函数作为条件：HAVING (sql语句)

例子1：having("sum(age) > 10")--->having sum(age) > 10（有sql注入风险）

例子2：having("sum(age) > {0}", 11)--->having sum(age) > 11（推荐使用）

拼接 OR： or()

例子：eq("id",1).or().eq("name","老王")--->id = 1 or name = \'老王\'

注意事项：主动调用or表示紧接着下一个方法不是用and连接!(不调用or则默认为使用and连接)

OR 嵌套：

例子：or(i -> i.eq("name", "李白").ne("status", "活着"))--->or (name = \'李白\' and status <> \'活着\')

AND 嵌套：

例子：and(i -> i.eq("name", "李白").ne("status", "活着"))--->and (name = \'李白\' and status <> \'活着\')

nested：正常嵌套 不带AND 或者 OR

例子：nested(i -> i.eq("name", "李白").ne("status", "活着"))--->(name = \'李白\' and status <> \'活着\')

拼接 sql：apply

例子1：apply("id = 1")--->id = 1

例子2：apply("date_format(dateColumn,\'%Y-%m-%d\') = \'2008-08-08\'")

              --->date_format(dateColumn,\'%Y-%m-%d\') = \'2008-08-08\'")

例子3：apply("date_format(dateColumn,\'%Y-%m-%d\') = {0}", "2008-08-08")

             --->date_format(dateColumn,\'%Y-%m-%d\') = \'2008-08-08\'")

注意事项：该方法可用于数据库函数 动态入参的params对应前面applySql内部的{index}部分.这样是不会有sql注入风险的,反之会有!

无视优化规则直接拼接到 sql 的最后：last

例子：last("limit 1")

注意事项：只能调用一次,多次调用以最后一次为准 有sql注入的风险,请谨慎使用

exists：拼接EXISTS（sql语句）

例子：exists("select id from table where age = 1")--->exists (select id from table where age = 1)

 

 

在学习过程中通过几个小例子(需求)验证了一下：

1.名字中包含雨并且年龄小于40   name like \'%雨%\' and age<40

 @Test
    public void selectByWrapper(){
        QueryWrapper<User> queryWrapper = new QueryWrapper<User>();
        //QueryWrapper<User> query = Wrappers.<User>query();
        queryWrapper.like("name","雨").lt("age",40);
        List<User> userList = userMapper.selectList(queryWrapper);
        userList.forEach(System.out::println);
    }

结果展示：

2.名字中包含雨年并且龄大于等于20且小于等于40并且email不为空   name like \'%雨%\' and age between 20 and 40 and email is not null

@Test
    public void selectByWrapper6(){
        QueryWrapper<User> queryWrapper = new QueryWrapper<>();
        queryWrapper.likeRight("name","王").or(qw->qw.lt("age",40).gt("age",20).isNotNull("email"));
        List<User> userList = userMapper.selectList(queryWrapper);
        for (User user : userList) {
            System.out.println(user);
        }
    }

结果展示：

3.名字为王姓或者年龄大于等于25，按照年龄降序排列，年龄相同按照id升序排列     name like \'王%\' or age>=25 order by age desc,id asc

  @Test
    public void selectByWrapper3(){
        QueryWrapper<User> queryWrapper = new QueryWrapper<User>();
        queryWrapper.likeRight("name","王").or().ge("age",25).orderByDesc("age").orderByAsc("id");
        List<User> userList = userMapper.selectList(queryWrapper);
        userList.forEach(System.out::println);
    }

结果展示：

4.创建日期为2019年2月14日并且直属上级为名字为王姓    date_format(create_time,\'%Y-%m-%d\')=\'2019-02-14\' and manager_id in (select id from user where name like \'王%\')

 @Test
    public void selectByWrapper4(){
        QueryWrapper<User> queryWrapper = new QueryWrapper<>();
        queryWrapper.apply("date_format(create_time,\'%Y-%m-%d\')={0}","2019-02-14")
                .inSql("manager_id","select id from mp_user where name like \'王%\'");
        List<User> userList = userMapper.selectList(queryWrapper);
        userList.forEach(System.out::println);
    }

结果展示：

5.名字为王姓并且（年龄小于40或邮箱不为空）     name like \'王%\' and (age<40 or email is not null)

 @Test
    public void selectByWrapper5(){
        QueryWrapper<User> queryWrapper = new QueryWrapper<>();
        queryWrapper.likeRight("name","王").and(wq->wq.lt("age",40).or().isNotNull("email"));
        List<User> userList = userMapper.selectList(queryWrapper);
        userList.forEach(System.out::println);
    }

结果展示：

6.名字为王姓或者（年龄小于40并且年龄大于20并且邮箱不为空）     name like \'王%\' or (age<40 and age>20 and email is not null)

 @Test
    public void selectByWrapper6(){
        QueryWrapper<User> queryWrapper = new QueryWrapper<>();
        queryWrapper.likeRight("name","王").or(qw->qw.lt("age",40).gt("age",20).isNotNull("email"));
        List<User> userList = userMapper.selectList(queryWrapper);
        for (User user : userList) {
            System.out.println(user);
        }
    }

结果展示：

7.（年龄小于40或邮箱不为空）并且名字为王姓            (age<40 or email is not null) and name like \'王%\'

@Test
    public void selectByWrapper7(){
        QueryWrapper<User> queryWrapper = new QueryWrapper<>();
        queryWrapper.nested(wq->wq.lt("age",40).or().isNotNull("email")).likeRight("name","王");
        List<User> userList = userMapper.selectList(queryWrapper);
        for (User user : userList) {
            System.out.println(user);
        }
    }

结果展示：

8.年龄为30、31、34、35            age in (30、31、34、35)

 @Test
    public void selectByWrapper8(){
        QueryWrapper<User> queryWrapper = new QueryWrapper<>();
        queryWrapper.in("age",Arrays.asList(30,31,34,35));
        //queryWrapper.in("age",30,31,34,35);
        List<User> userList = userMapper.selectList(queryWrapper);
        for (User user : userList) {
            System.out.println(user);
        }
    }

结果展示：

9、只返回满足条件的其中一条语句即可       limit 1

@Test
    public void selectByWrapper9(){
        QueryWrapper<User> queryWrapper = new QueryWrapper<>();
        queryWrapper.in("age",Arrays.asList(30,31,34,35)).last("limit 1");
        List<User> userList = userMapper.selectList(queryWrapper);
        for (User user : userList) {
            System.out.println(user);
        }
    }

结果展示：

以上仅为一些简单的需求，后续学习使用复杂的用法再进行记录整理。。。。。。。