java下double乘以100后精度丢失问题

Posted 2021-03-17 以德为先

比如

System.out.println(0.14*100);

输出： 14.000000000000002

 

解决方法：

BigDecimal b = new BigDecimal(String.valueOf(0.14));
BigDecimal c = new BigDecimal(String.valueOf(100));
System.out.println(b.multiply(c));
System.out.println(b.multiply(c).intValue());
System.out.println(b.multiply(c).doubleValue());

输出： 

14.00
14
14.0