SpringBoot-01-快速入门(IEDA)

Posted 2021-03-13 DingJie1024

1.1 创建Maven工程

使用idea工具创建一个maven工程，该工程为普通的java工程即可

 

 

 

 

 

 

 

 1.2 添加SpringBoot的起步依赖

SpringBoot要求，项目要继承SpringBoot的起步依赖spring-boot-starter-parent

<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>2.0.1.RELEASE</version>
</parent>

SpringBoot要集成SpringMVC进行Controller的开发，所以项目要导入web的启动依赖

<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
</dependencies>

1.3 编写SpringBoot引导类

要通过SpringBoot提供的引导类起步SpringBoot才可以进行访问

package com.itheima;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
@SpringBootApplication
public class MySpringBootApplication {
　　public static void main(String[] args) {
　　　　SpringApplication.run(MySpringBootApplication.class);
　　}
}

1.4 编写Controller

在引导类MySpringBootApplication同级包或者子级包中创建QuickStartController

package com.itheima.controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.ResponseBody;
@Controller
public class QuickStartController {
    @RequestMapping("/quick")
    @ResponseBody
    public String quick(){
        return "springboot 访问成功!";
    }
}