Java 8 – Convert List to Map
Posted Blogger
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了Java 8 – Convert List to Map相关的知识,希望对你有一定的参考价值。
Java 8 – Convert List to Map
package com.mkyong.java8
public class Hosting {
private int Id;
private String name;
private long websites;
public Hosting(int id, String name, long websites) {
Id = id;
this.name = name;
this.websites = websites;
}
//getters, setters and toString()
}
1. List to Map – Collectors.toMap()
package com.mkyong.java8
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;
public class TestListMap {
public static void main(String[] args) {
List<Hosting> list = new ArrayList<>();
list.add(new Hosting(1, "liquidweb.com", 80000));
list.add(new Hosting(2, "linode.com", 90000));
list.add(new Hosting(3, "digitalocean.com", 120000));
list.add(new Hosting(4, "aws.amazon.com", 200000));
list.add(new Hosting(5, "mkyong.com", 1));
// key = id, value - websites
Map<Integer, String> result1 = list.stream().collect(
Collectors.toMap(Hosting::getId, Hosting::getName));
System.out.println("Result 1 : " + result1);
// key = name, value - websites
Map<String, Long> result2 = list.stream().collect(
Collectors.toMap(Hosting::getName, Hosting::getWebsites));
System.out.println("Result 2 : " + result2);
// Same with result1, just different syntax
// key = id, value = name
Map<Integer, String> result3 = list.stream().collect(
Collectors.toMap(x -> x.getId(), x -> x.getName()));
System.out.println("Result 3 : " + result3);
}
}
Output
Result 1 : {1=liquidweb.com, 2=linode.com, 3=digitalocean.com, 4=aws.amazon.com, 5=mkyong.com}
Result 2 : {liquidweb.com=80000, mkyong.com=1, digitalocean.com=120000, aws.amazon.com=200000, linode.com=90000}
Result 3 : {1=liquidweb.com, 2=linode.com, 3=digitalocean.com, 4=aws.amazon.com, 5=mkyong.com}
2. List to Map – Duplicated Key!
package com.mkyong.java8;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;
public class TestDuplicatedKey {
public static void main(String[] args) {
List<Hosting> list = new ArrayList<>();
list.add(new Hosting(1, "liquidweb.com", 80000));
list.add(new Hosting(2, "linode.com", 90000));
list.add(new Hosting(3, "digitalocean.com", 120000));
list.add(new Hosting(4, "aws.amazon.com", 200000));
list.add(new Hosting(5, "mkyong.com", 1));
list.add(new Hosting(6, "linode.com", 100000)); // new line
// key = name, value - websites , but the key ‘linode‘ is duplicated!?
Map<String, Long> result1 = list.stream().collect(
Collectors.toMap(Hosting::getName, Hosting::getWebsites));
System.out.println("Result 1 : " + result1);
}
}
Output – The error message below is a bit misleading, it should show “linode” instead of the value of the key.
Exception in thread "main" java.lang.IllegalStateException: Duplicate key 90000
at java.util.stream.Collectors.lambda$throwingMerger$0(Collectors.java:133)
at java.util.HashMap.merge(HashMap.java:1245)
//...
2.2 To solve the duplicated key issue above, pass in the third mergeFunction argument like this :
Map<String, Long> result1 = list.stream().collect(
Collectors.toMap(Hosting::getName, Hosting::getWebsites,
(oldValue, newValue) -> oldValue
)
);
Output
Result 1 : {..., aws.amazon.com=200000, linode.com=90000}
Copy
Note
(oldValue, newValue) -> oldValue ==> If the key is duplicated, do you prefer oldKey or newKey?
3.3 Try newValue
Map<String, Long> result1 = list.stream().collect(
Collectors.toMap(Hosting::getName, Hosting::getWebsites,
(oldValue, newValue) -> newvalue
)
);
Output
Result 1 : {..., aws.amazon.com=200000, linode.com=100000}
3. List to Map – Sort & Collect
package com.mkyong.java8;
import java.util.*;
import java.util.stream.Collectors;
public class TestSortCollect {
public static void main(String[] args) {
List<Hosting> list = new ArrayList<>();
list.add(new Hosting(1, "liquidweb.com", 80000));
list.add(new Hosting(2, "linode.com", 90000));
list.add(new Hosting(3, "digitalocean.com", 120000));
list.add(new Hosting(4, "aws.amazon.com", 200000));
list.add(new Hosting(5, "mkyong.com", 1));
list.add(new Hosting(6, "linode.com", 100000));
//example 1
Map result1 = list.stream()
.sorted(Comparator.comparingLong(Hosting::getWebsites).reversed())
.collect(
Collectors.toMap(
Hosting::getName, Hosting::getWebsites, // key = name, value = websites
(oldValue, newValue) -> oldValue, // if same key, take the old key
LinkedHashMap::new // returns a LinkedHashMap, keep order
));
System.out.println("Result 1 : " + result1);
}
}
Result 1 : {aws.amazon.com=200000, digitalocean.com=120000, linode.com=100000, liquidweb.com=80000, mkyong.com=1}
http://www.mkyong.com/java8/java-8-convert-list-to-map/
以上是关于Java 8 – Convert List to Map的主要内容,如果未能解决你的问题,请参考以下文章
Python convert list string to list
Convert Sorted Array to Binary Search Tree & Convert Sorted List to Binary Search Tree
Add to List 538. Convert BST to Greater Tree
leetcode 109 Convert Sorted List to Binary Search Tree
Failed to convert value of type ‘java.lang.String‘ to required type ‘java.util.Date‘;