蓝桥网试题 java 基础练习 矩形面积交

Posted 2020-08-20 Luking

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思路见锦囊2

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算法

 1 import java.util.Scanner;
 2 public class Main {
 3     public static void main(String[] args) {
 4         Scanner sc = new Scanner(System.in);
 5         double[] x = new double[4];
 6         double[] y = new double[4];
 7         double[] z = new double[4];
 8         for(int i=0;i<4;i++){
 9             x[i] = sc.nextDouble();
10             y[i] = sc.nextDouble();
11         }
12         z[0] = Math.max(Math.min(x[0], x[1]),Math.min(x[2], x[3])); //x1
13         z[1] = Math.min(Math.max(x[0], x[1]),Math.max(x[2], x[3])); //x2
14         
15         z[2] = Math.max(Math.min(y[0], y[1]),Math.min(y[2], y[3])); //y1
16         z[3] = Math.min(Math.max(y[0], y[1]),Math.max(y[2], y[3])); //y2
17         if(z[0]<z[1]&&z[2]<z[3])
18             System.out.printf("%.2f\\n",(z[1]-z[0])*(z[3]-z[2]));
19         else
20             System.out.println("0.00");
21     }
22 }