排序相关的问题(jq,java)_1123

Posted 2020-08-20

数据list<String,Object> behaviorData如下：

我要做的是把这个list里面占百分比前四名（除了[0]的那个百分百的）的数据显示出来。显示在页面上。

List<BehaviorData> behaviorData = this.behaviorService.searchBehaviorByCondition(behaviorAnalysis);
//        通过循环计算出违法行为top4
        float[] behaviorTop4 = new float[behaviorData.size()-1];
        for (int i = 1; i <behaviorData.size() ; i++) {
            String percent = behaviorData.get(i).getViolationProportion();
            if (percent!=null){
                behaviorTop4[i-1] = Float.parseFloat(percent.replace("%",""));
            }
        }
        Arrays.sort(behaviorTop4);
        List<BehaviorData> behaviorNum4 = new ArrayList<BehaviorData>();
        for (int i = 1; i <=4 ; i++) {
            Float x= behaviorTop4[behaviorTop4.length-i];
            DecimalFormat df = new DecimalFormat("0.00");
            df.format(x);
            String value = x+"%";
            for (int j = 0; j < behaviorData.size(); j++) {
                if (value.equals(behaviorData.get(j).getViolationProportion())){
                    BehaviorData mer = new BehaviorData();
                    mer.setViolationProportion(value) ;
                    mer.setBehaviorName(behaviorData.get(j).getBehaviorName());
                    behaviorNum4.add(mer);
                    break;
                }
            }
        }