spring用xml装配bean的方法

Posted 2020-11-22 yyy116008

使用XML装配bean，在bean中调用另一个bean方法，首先建一个Dog类和一个Cat类

package soundsystem;

public class Dog {

private String Cry;//叫声

//用setter方法注入
public void setCry(String cry) {
    Cry = cry;
}

//定义一个狗叫方法
    public void DogCry(){
        System.out.println("狗叫："+Cry);
        Cat.CatCry();
        catEat.CatEating();
    }
}

package soundsystem;

public class Cat {
    private String Cry;//叫声

//用构造函数注入
    public Cat(String cry){
        this.Cry=cry;
    }

//定义一个猫叫方法
    public void CatCry(){
        System.out.println("猫叫："+Cry);
    }
}

 

一个配置类Bean_DogXML.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

    <bean id="Dog" class="soundsystem.Dog">
        <property name="Cry" value="汪汪汪~"></property>
        <property name="Cat" ref="Cat"></property>
    </bean>

    <bean id="Cat" class="soundsystem.Cat">
        <constructor-arg value="喵~"></constructor-arg>
    </bean>

</beans>

 

现在开始测试

package Test;

import org.junit.runner.RunWith;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import org.springframework.test.context.junit4.SpringJUnit4ClassRunner;
import soundsystem.Cat;
import soundsystem.Dog;

@RunWith(SpringJUnit4ClassRunner.class)
public class Test {

    @org.junit.Test
    public static void main(String[] args) {
        ApplicationContext ap=new ClassPathXmlApplicationContext("config/Bean_DogXML.xml");
        Dog dog=(Dog)ap.getBean("Dog");
        dog.DogCry();
    }
}

 

输出结果：