java编程思想-第13章-某些练习题
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. 匹配任意一个字符
* 表示匹配0个或多个前面这个字符
+ 表示1个或多个前面这个字符
? 表示0个或1个前面这个字符
^ 表示一行的开始 ^[a-zA-Z] ：表示开头是a-z或者A-Z
[^0-9] ：表示不是数字，除数字以外的
$ 表示一行的结束
第七题:
public class Test7 {
public static void main(String[] args) {
//两种写法都可以
String regex = "^[A-Z].*\\.$";//"^[A-Z].*\\."这样也对
String regex1 = "\\p{Upper}.*\\.$";
String str = "D.";
String str1 = "Dfasdfasfasfdasfdasfasfasdf.";
String str2 = "Dfasdfasfasfdasfdasfasfasdf.E";
System.out.println(str.matches(regex));
System.out.println(str1.matches(regex));
System.out.println(str2.matches(regex));
System.out.println(str.matches(regex1));
System.out.println(str1.matches(regex1));
System.out.println(str2.matches(regex1));
}
}
运行结果:
true
false
true
true
false
第八题
package net.mindview.strings;
import java.util.Arrays;
public class Splitting {
public static String knights = "Then, when you have found the shrubbery, you must cut down the mightiest tree in the forest... with... a herring!";
public static void split(String regex){
System.out.println(Arrays.toString(knights.split(regex)));
}
public static void main(String[] args) {
//表示的时按照空格分割字符串
//运行结果:[Then,, when, you, have, found, the, shrubbery,, you, must, cut, down, the, mightiest, tree, in, the, forest..., with..., a, herring!]
split(" ");
//表示按照非单次字符分割字符串--这里的非单次字符是空格和,
//运行结果:[Then, when, you, have, found, the, shrubbery, you, must, cut, down, the, mightiest, tree, in, the, forest, with, a, herring]
split("\\W+");
//这个表示:费单次字符之前带n的地方进行分割字符串 这里的分割符是n空格和n,
//运行结果:[The, whe, you have found the shrubbery, you must cut dow, the mightiest tree i, the forest... with... a herring!]
split("n\\W+");
}
}
package net.mindview.strings.test8;
import net.mindview.strings.Splitting;
public class Test8 {
public static void main(String[] args) {
String regex = "the|you";
Splitting.split(regex);
}
}
第九题
package net.mindview.strings.test9;
import net.mindview.strings.Splitting;
public class Test9 {
public static void main(String[] args) {
String regex = "A|E|I|O|U|a|e|i|o|u";
//通过嵌入式标志表达式 (?i) 也可以启用不区分大小写的匹配。
String regex1 = "(?i)a|e|i|o|u";
//[abc] 表示a或b或c
String regex2 = "(?i)[aeiou]";
System.out.println(Splitting.knights.replaceAll(regex, "_"));
System.out.println(Splitting.knights.replaceAll(regex1, "_"));
System.out.println(Splitting.knights.replaceAll(regex2, "_"));
}
}
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