Java中List集合去除重复数据的方法

Posted 2020-10-29 段桥123

 

1. 循环list中的所有元素然后删除重复

public   static   List  removeDuplicate(List list)  {       
  for  ( int  i  =   0 ; i  <  list.size()  -   1 ; i ++ )  {       
      for  ( int  j  =  list.size()  -   1 ; j  >  i; j -- )  {       
           if  (list.get(j).equals(list.get(i)))  {       
              list.remove(j);       
            }        
        }        
      }        
    return list;       
}  

2. 通过HashSet踢除重复元素

public static List removeDuplicate(List list) {   
    HashSet h = new HashSet(list);   
    list.clear();   
    list.addAll(h);   
    return list;   
}   

3. 删除ArrayList中重复元素，保持顺序

// 删除ArrayList中重复元素，保持顺序     
 public static void removeDuplicateWithOrder(List list) {    
    Set set = new HashSet();    
     List newList = new ArrayList();    
   for (Iterator iter = list.iterator(); iter.hasNext();) {    
         Object element = iter.next();    
         if (set.add(element))    
            newList.add(element);    
      }     
     list.clear();    
     list.addAll(newList);    
    System.out.println( " remove duplicate " + list);    
 }   

4.把list里的对象遍历一遍，用list.contain()，如果不存在就放入到另外一个list集合中

public static List removeDuplicate(List list){  
        List listTemp = new ArrayList();  
        for(int i=0;i<list.size();i++){  
            if(!listTemp.contains(list.get(i))){  
                listTemp.add(list.get(i));  
            }  
        }  
        return listTemp;  
    }  

 

 

 

Set<String> s = new HashSet<String>();
for(int i=0;i<list.size();i++){
    boolean b = s.add(list.get(i));
    if(!b){
        System.out.println("重复值===================================："+list.get(i));
    }
}