C++ 字符串与16进制字符串之间的转换

Posted 2023-04-07

用C++实现字符串与16进制字符串之间的转换，就是说，C++中的string类型的任意字符串转换成16进制表示的string类型的字符串，反之亦然。应该是将string中的每一个字符转换成相应的ascii码值，再把所有的16进制的ascii码值用字符串的形式联系起来。跪求代码！！！

staticintstr_to_hex(char*string,unsignedchar*cbuf,intlen)

BYTEhigh,low;

intidx,ii=0;

for(idx=0;idx<len;idx+=2)

high=string[idx];

low=string[idx+1];

if(high>='0'&&high<='9')

high=high-'0';

elseif(high>='A'&&high<='F')

high=high-'A'+10;

elseif(high>='a'&&high<='f')

high=high-'a'+10;

else

return-1;

if(low>='0'&&low<='9')

low=low-'0';

elseif(low>='A'&&low<='F')

low=low-'A'+10;

elseif(low>='a'&&low<='f')

low=low-'a'+10;

else

return-1;

cbuf[ii++]=high<<4|low;

return0;

/****************************************************************************

函数名称:hex_to_str

函数功能:十六进制转字符串

输入参数:ptr字符串buf十六进制len十六进制字符串的长度。

输出参数:无

*****************************************************************************/

staticvoidhex_to_str(char*ptr,unsignedchar*buf,intlen)

for(inti=0;i<len;i++)

sprintf(ptr,"%02x",buf[i]);

ptr+=2;

扩展资料

byte数组转十六进制字符串

publicstaticStringbyteArraytoHexString(byte[]b)

intiLen=b.length;

StringBuffersb=newStringBuffer(iLen*2);

for(inti=0;i<iLen;i++)

intintTmp=b[i];

while(intTmp<0)

intTmp=intTmp+256;

if(intTmp<16)

sb.append("0");

sb.append(Integer.toString(intTmp,16));

returnsb.toString().toUpperCase();

参考技术A #typedef unsinged char BYTE;
#include <string>
#include <vector>
#include <sstream>

std::vector<BYTE> str_to_hex(const std::string& str)

if (str.size() != str.size() / 2 * 2)
str = "0" + str;
std::vector<BYTE> vec;
std::stringstream ss;
ss << std::hex;
for (std::string::size_type ix = 0; ix != str.size() / 2; ++ix)
int val = 0;
ss << str.substr(ix * 2, 2);
ss >> val;
vec.push_back(val);
ss.clear();

return vec;


另一个反过来自己写吧！追问

自定义的函数的参量和返回值都是string类型的才行啊，你写的返回值不对啊

追答

#include

std::string hex_to_str(const std::vector& vec)

std::ostringstream oss;
oss << std::setw(2) << std::setfill('0') << std::hex;
for (auto iter = vec.begin(); iter != vec.end(); ++iter)
oss << *iter;



return oss.str();

参考技术B #include <stdio.h>
int main()

char szValue[] = "0x11";
char ch[32];
int nValude = 0;
sscanf(szValue,"%x",&nValude); //十六进制转数字
sprintf(ch,"%d",nValude); //数字转字符
printf("%d/n",nValude);
return 0;

http://baike.baidu.com/view/1364018.htm
http://baike.baidu.com/view/1295144.htm
http://blog.csdn.net/delphiwcdj/article/details/4649854/ 参考这里

C# 二进制与字符串之间的相互转换

/// <summary>
    /// 将字符串转成二进制
    /// </summary>
    /// <param name="s"></param>
    /// <returns></returns>
    public static string bianma(string s)
    {
        byte[] data = Encoding.Unicode.GetBytes(s);
        StringBuilder result = new StringBuilder(data.Length * 8);

        foreach (byte b in data)
        {
            result.Append(Convert.ToString(b, 2).PadLeft(8, ‘0‘));
        }
        return result.ToString();
    }

 

/// <summary>
    /// 将二进制转成字符串
    /// </summary>
    /// <param name="s"></param>
    /// <returns></returns>
    public static string jiema(string s)
    {
        System.Text.RegularExpressions.CaptureCollection cs =
            System.Text.RegularExpressions.Regex.Match(s, @"([01]{8})+").Groups[1].Captures;
        byte[] data = new byte[cs.Count];
        for (int i = 0; i < cs.Count; i++)
        {
            data[i] = Convert.ToByte(cs[i].Value, 2);
        }
        return Encoding.Unicode.GetString(data, 0, data.Length);
    }