安装SQL Server 2014的坎坷之路（安装中遇到的错误以及解决方案）

Posted 2023-04-04 余生有梦 ysym

目录

目录

一、SQL Server 2014下载、安装与使用

二、SQL Server 2014安装的坎坷之路

1、解决SQL安装规则需要 Microsoft .NET Framework 3.5 Service Pack 1失败

（1）检查电脑中是否有net 3.5

 （2）安装net 3.5

2.解决“未能加载文件或程序集"Microsoft.SqlServer.Sqm, Version=12.0.0.0,Culture=neutral”问题

3、解决“error: 40”

4、未解决错误：提示SSIS安装异常

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一、SQL Server 2014下载、安装与使用

SQL Server 2014下载，安装和使用教程_李奇同学的博客-CSDN博客_sqlserver2014本文主要讲解数据库软件SQL Server 2014下载，安装和使用，都是个人亲身经历，特此记录！https://blog.csdn.net/qq_34885913/article/details/99555496这是我下载和安装所使用的教程，是李奇同学写的，里面有提供下载链接！

下载链接：https://pan.baidu.com/s/1AbuEloUEMLsCc6AC5HPPOg
提取码：6ifv
适用对象：Windows (64位）

二、SQL Server 2014安装的坎坷之路

1、解决SQL安装规则需要 Microsoft .NET Framework 3.5 Service Pack 1失败

（1）检查电脑中是否有net 3.5

1、打开控制面板

 2、点击“程序”

3、点击“启用或关闭Windows功能”

 4、如果net 3.5没有被选中，则说明需要安装

​​​

 （2）安装net 3.5

 下载链接：https://www.microsoft.com/zh-CN/download/details.aspx?id=22

 点击蓝色链接，选择语言后，点击下载

注意：此时无法直接安装

1、点击 “Win +R"，输入"services msc"，回车

2、找到 Windows Upde服务，右键关闭，再进行启动，重启设备

 这里注意，一定要重启，否则可能也没用

然后继续返回安装SQL Server即可

2.解决“未能加载文件或程序集"Microsoft.SqlServer.Sqm, Version=12.0.0.0,Culture=neutral”问题

微软下载链接：https://www.microsoft.com/zh-cn/download/details.aspx?id=35747

  1、点击蓝色链接，选择语言后，点击下载

 2、下载后点击安装又有了新的错误

安装程序缺少一个安装必备组件:

- Microsoft System CLR Types for sQL Server 2012

我真的栓Q.....找了一大圈都是要钱的，需要开会员什么的，在微软也找不到下载地址啥的搞了很久之后我发现，还是点击刚才蓝色的链接，就可以找到这个组件.......

3、下载Microsoft System CLR Types for sQL Server 2012

下载链接：https://www.microsoft.com/zh-cn/download/details.aspx?id=35747

 但是我又发现直接点击一直没反应....

4、右击，选择“在新窗口中打开”，然后刷新几次就可以下载了

5、先安装Microsoft System CLR Types for sQL Server 2012，然后再安装前面下载的MICROSOFT REPORT VIEWER 2012 RUNTIM就可以安装成功了！

3、解决“error: 40”

在与 SQL Server 建立连接时出现与网络相关的或特定于实例的错误。未找到或无法访问服务器。请验证实例名称是否正确并且 SQL Server 已配置为允许远程连接。 (provider: 命名管道提供程序, error: 40 - 无法打开到 SQL Server 的连接

1、在开始菜单找到 “ SQL Server 2014 配置管理器 ”并打开

 

 2、先点击"SQL Server 网络配置"，然后点击“MSSQLSERVER的协议”

 3、右击启用“TCP/IP协议”

4、未解决错误：提示SSIS安装异常

修复了也不行.....但是我也不知道有啥用，所以先这样放着吧，我实在是累了......

???Sql Server???SQL SERVER ????????????

?????????int   with   ??????   serve   span   ??????   inner   --   blog   

??????:???Sql Server???SQL SERVER ????????????

??????SQL SERVER 2005?????????????????????????????????????????????SQL SERVER 2005???????????????CTE?????????????????????CTE?????????????????????

??????CTE??????????????????Common Table Expression ???SQL SERVER 2005????????????????????????????????????

#??????????????????

1???sql

 1 Create table GroupInfo([Id] int,[GroupName] nvarchar(50),[ParentGroupId] int)
 2 
 3 Insert GroupInfo
 4 
 5 select 0,??????????????????,null union all
 6 
 7 select 1,??????????????????,0 union all
 8 select 2,??????????????????,1 union all
 9 select 3,??????????????????,1 union all
10 select 4,????????????????????????,2 union all
11 select 5,????????????????????????,2 union all
12 select 6,????????????????????????,3 union all
13 select 7,????????????????????????,3 union all
14 
15 select 8, ???????????????,0 union all
16 select 9, ?????????????????????,8 union all
17 select 10,????????????????????????,8 union all
18 select 11,???????????????????????????,9 union all
19 select 12,???????????????????????????,9 union all
20 select 13,??????????????????????????????,10 union all
21 select 14,??????????????????????????????,10 

2????????????

 

#????????????Demo

1???????????????????????????????????????????????????,???????????????????????????

 1 --????????????????????????????????????????????????
 2 with
 3 CTE
 4 as
 5 (
 6     select * from GroupInfo where Id=1
 7     union all
 8     select G.* from CTE inner join GroupInfo as G
 9     on CTE.Id=G.ParentGroupId
10 )
11 select * from CTE order by Id

 

 1 --????????????????????????????????????????????????
 2 with
 3 CTE
 4 as
 5 (
 6     select * from GroupInfo where Id=14
 7     union all
 8     select G.* from CTE inner join GroupInfo as G
 9     on CTE.ParentGroupId=G.Id
10 )
11 select * from CTE order by Id

2?????????????????????

 1 --??????????????????
 2 with
 3 CTE
 4 as
 5 (
 6     select Id,GroupName,ParentGroupId,GroupPath=CAST( GroupName as nvarchar(max)) from GroupInfo where Id=1
 7     union all
 8     select G.*,CAST(CTE.GroupPath+???//???+G.GroupName as nvarchar(max)) as GroupPath from CTE 
 9     inner join GroupInfo as G
10     on CTE.Id=G.ParentGroupId
11 )
12 select * from CTE

 3?????????????????????????????????????????????????????????

 1 --??????id????????????????????????????????????sort??????????????????sort??????????????????????????????????????????????????????
 2 WITH    
 3 CTE
 4 AS 
 5 ( 
 6     SELECT * ,CAST(RIGHT(???000??? + CAST([Id] AS VARCHAR), 3) AS VARCHAR(MAX)) AS sort FROM GroupInfo
 7     WHERE ParentGroupId = 0
 8     UNION ALL
 9     SELECT   GroupInfo.* ,CAST(sort + RIGHT(???000??? + CAST(GroupInfo.[Id] AS VARCHAR),3) AS VARCHAR(MAX)) AS sort
10     FROM CTE
11     INNER JOIN GroupInfo ON CTE.Id = GroupInfo.ParentGroupId
12 )
13 SELECT * FROM CTE ORDER BY sort 

 

4?????????????????????????????????????????????????????????

1 --??????????????????
2 WITH CTE AS (
3     SELECT *,1 AS [Level] FROM GroupInfo WHERE ParentGroupId=0
4     UNION ALL
5     SELECT G.*,CTE.Level+1 FROM GroupInfo as G 
6     JOIN CTE ON CTE.Id =G.ParentGroupId
7 )
8 SELECT * FROM CTE