怎么实现struts2和spring的整合

Posted 2020-10-14

第一步创建spring配置文件applicationContext.xml。该配置负责导入处理业务bean和持久化bean的配置，添加对controller层的action bean管理的支持。此文件一般放在WEB-INF文件夹下，如下：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">


    <!-- 导入spring配置 -->
    <import resource="spring-service.xml" />
    <import resource="spring-dao.xml" />
    
    <!-- 打开组件扫描controller，将action对象管理起来 -->
    <context:component-scan base-package="com.entor.rams.actions">
        <!-- 只对@Controller -->
        <context:include-filter type="annotation"
            expression="org.springframework.stereotype.Controller" />
    </context:component-scan>
</beans>

 

第二步配置struts2的核心配置struts.xml;负责处理controller层的action bean以及前端控制功能，声明action对象的管理交给spring容器。

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.5//EN"
"http://struts.apache.org/dtds/struts-2.5.dtd">
<struts>
    <!-- 常量 -->
    <!-- 开发模式打开 -->
    <constant name="struts.devMode" value="true" />
    <!-- 声明action对象的管理交给spring容器 -->
    <constant name="struts.objectFactory" value="spring"></constant>
    <!--通过ACTION的限制得到的结果页面路径  -->
    <constant name="struts.convention.result.path" value="/WEB-INF/jsps/"></constant>
    
    <!-- action配置： 包 命名空间 action, result等 -->
    <!-- <package name="zijiding" extends="struts-default" namespace="/">
        name表示请求的url：/rams/user_*
        class表示请求的处理action对象
        method表示处理请求的方法名，{1}与name中第一次出现的通配符关联
        <action name="user_*" class="userAction" method="{1}">
        result表示响应的结果，此处响应webapp根目录下面的index.jsp页面
            <result name="success">/WEB-INF/jsps/result.jsp</result>
        </action> -->
    <!-- </package> -->
</struts>

 

 

第三步配置Struts-Spring集成设置web.xml, 该配置主要

1.配置web监听器ContextLoaderListener 监听spring上下文对象；

2.初始化Spring容器，加载spring核心配置文件;

3.配置struts过滤器，接管所有的请求。如下所示：

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    id="WebApp_ID" version="3.0">
    <display-name>RAMSMY</display-name>

    <!-- 首页 -->
    <welcome-file-list>
        <welcome-file>/index</welcome-file>
    </welcome-file-list>
    
    <!-- web监听 -->
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    
    <!-- 初始化spring容器,加载spring核心配置文件 -->
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/configs/applicationContext.xml</param-value>
    </context-param>
    
    <!-- 配置struts过滤器，接管所有的请求 -->
    <!-- 默认加载classpath路径下面的struts.xml -->
    <filter>
        <filter-name>struts2</filter-name>
        <filter-class>org.apache.struts2.dispatcher.filter.StrutsPrepareAndExecuteFilter</filter-class>
    </filter>
    <filter-mapping>
        <filter-name>struts2</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>
</web-app>

主要配置文件已完成后新建，创建一个User.java类，提供get set 方法。

然后写好dao层和service层。新建action类UserAction.java,如下：

package com.entor.rams.actions;

import java.io.Serializable;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpSession;

import org.apache.struts2.ServletActionContext;
import org.apache.struts2.convention.annotation.Action;
import org.apache.struts2.convention.annotation.Result;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;

import com.entor.rams.domain.User;
import com.entor.rams.service.UserService;
import com.entor.rams.utils.common.RamsConstants;
import com.opensymphony.xwork2.ActionSupport;
import com.opensymphony.xwork2.ModelDriven;

@Controller
public class UserAction extends ActionSupport implements ModelDriven<User>,Serializable{

    private static final long serialVersionUID =483187020462134967L;
    
    @Autowired
    private UserService userService;
    
    private User user;
    
    public User getUser() {
        return user;
    }
    @Override
    public User getModel() {
        if(user == null)
            this.user =new User();
        return user;
    }
    /**
     * 处理请求首页
     * @return
     */
    @Action(value = "index", className = "userAction" , results = //
            @Result(name = "success", location = "index.jsp"))
    public String index(){
        return SUCCESS;
    }
    
    /**
     * 处理登陆请求
     * @return
     */
    @Action(value="user_login",className="userAction",results={
            @Result(name = "success",location = "result.jsp"),//
            @Result(name = "fail",location = "index.jsp")})
    public String login(){
        //取出请求和会话对象
        HttpServletRequest request = ServletActionContext.getRequest();
        HttpSession session = request.getSession(false);
        
        User u = userService.fingByLoginNameAndPassword(this.user.getLoginName(), this.user.getPassword());
        
        //用户登陆成功
        if(u !=null){
            this.user = u;
            session.setAttribute(RamsConstants.USER_SESSION, user);
            return SUCCESS;
        }
        //用户登陆失败
        else{
            String errorMsg = "用户名或密码错误";
            request.setAttribute("errorMsg", errorMsg);
            return RamsConstants.FAIL;
        }
    }
}

 

最后测试结果如下：