Image.FromStream 参数无效

Posted 2023-03-26

想实现数据库存取图片，保存时没事，读取时用下面的方法
byte[] mydata = ((byte[])（/*数据库返回值*/）);
MemoryStream ms = new MemoryStream(mydata);
ms.Position = 0;
ms.Read(mydata, 0, Convert.ToInt32(ms.Length));
Image img = Image.FromStream(ms);
ms.Close();

Image img = Image.FromStream(ms);这一句提示参数无效，怎么办啊

有没有别的简单的数据库存取图片方法也行的

参考技术A //将上传的文件转换到二进制编码

//'*******************************************
int filelength;
HttpPostedFile upfile;
upfile = lofile.PostedFile;
filelength = upfile.ContentLength; //记录文件长度
byte[] FileByteArray = new Byte[filelength]; //图象文件临时储存Byte数组
Stream StreamObject = upfile.InputStream; //建立数据流对像
StreamObject.Read(FileByteArray, 0, filelength);
filesize = upfile.ContentLength;
filelx = upfile.ContentType.ToString();

//*******************************************

//读取文件
filename = myset2.Tables["temps"].Rows[0]["SysS_FileName"].ToString();
filesize = int.Parse(myset2.Tables["temps"].Rows[0]["SysS_FileSize"].ToString());
filetype = myset2.Tables["temps"].Rows[0]["SysS_FileType"].ToString();
//Dim fileimge(filesize) As Byte
//fileimge = myset2.Tables("temps").Rows(0).Item("SysS_FileImage")
byte[] fileimge = new Byte[filesize];
fileimge = (byte[])myset2.Tables["temps"].Rows[0]["SysS_FileImage"];
Response.ContentType = filetype; //设定输出文件类型

Response.Charset = "GB2312";
Response.ContentEncoding = System.Text.Encoding.UTF8;
Response.AddHeader("Content-Disposition", "inline; filename=" + HttpUtility.UrlEncode(System.Text.Encoding.UTF8.GetBytes(filename)));//输出方式,在浏览器打开.
//Response.AddHeader("Content-Disposition", "attachment;filename=" + HttpUtility.UrlEncode(System.Text.Encoding.UTF8.GetBytes(filename)));//以文件方式打开

Response.BinaryWrite(fileimge);
// Response.OutputStream.Write(fileimge, 0, filesize)
myset2.Dispose();