Java lambda 怎么在list转换map时，把多个参数拼接作为key

Posted 2023-03-23

List<Parts> synList = partsMapper.getPartGroupByVehicleIdOfSyn(parts);
Map<String,Parts> partsMap = new HashMap<>();
for(Parts _parts : synList)
partsMap.put(_parts.getOe()+_parts.getOeId()+_parts.getPartGroupId()+_parts.getStdPartId()+_parts.getBrandCode(),_parts);


如何把以上代码的List转为map集合改为lambda实现

参考技术A

代码如下：

Map<String, Parts> synOeMap = synList.stream()
    .collect(Collectors.toMap(k -> k.getOe()+k.getOeId()+k.getPartGroupId()+k.getStdPartId()+k.getBrandCode(), synOe -> synOe));

本回答被提问者采纳 参考技术B as .forEach(n -> a1s.add(n.a1));追问

Map synOeMap = synList.stream().collect(Collectors.toMap(Parts ::getOe, synOe -> synOe)); 如果是这条语句该怎么改？