java编程将26个字母按形如手机键盘的对应形式转换成0~9数字

Posted 2023-03-20

写一个方法格式是public static String wordToSignature(String word)，方法返回一个数字串，比如home就返回4663，如果里面包含不是26个字母的字符，就返回空格，用stringBuffer来写，谢谢各位大哥大姐帮回答一下！Write the method wordToSignature with the type: public static String wordToSignature(String word)The method takes a word and returns a numeric signature. e.g. “home” should return “4663”. If the word has any non-alphabetic characters, replace them with a “ ” (space) in the resulting signature. Accumulate the result character-by-character.

参考技术A public static String wordToSignature(String word)
word = word.toLowerCase();
StringBuffer sb = new StringBuffer();
for (int i = 0; i < word.length(); i++)
char c = word.charAt(i);
if (c == 'a' || c == 'b' || c == 'c')
sb.append('2');
else if (c == 'd' || c == 'e' || c == 'f')
sb.append('3');
else if (c == 'g' || c == 'h' || c == 'i')
sb.append('4');
else if (c == 'j' || c == 'k' || c == 'l')
sb.append('5');
else if (c == 'm' || c == 'n' || c == 'o')
sb.append('6');
else if (c == 'p' || c == 'q' || c == 'r' || c == 's')
sb.append('7');
else if (c == 't' || c == 'u' || c == 'v')
sb.append('8');
else if (c == 'w' || c == 'x' || c == 'y' || c == 'z')
sb.append('9');
else
return " ";


return sb.toString();
参考技术B 兄弟 加个微信 和你一个学校