对于Hibernbate SQLServer 2008 No Dialect mapping for JDBC type:-9解决方法

Posted 2023-03-07 KdanMin

今天同事遇到一个hibernate.mapping.exception,然后帮忙解决啦！下面整理下解决方法

异常重现

第一种通过整理hibernate.cfg.xml  Dialect

package com.util;


import java.sql.Types;


import org.hibernate.Hibernate;
import org.hibernate.dialect.SQLServerDialect;

public class MyDialect extends SQLServerDialect
public MyDialect()
super();

               //对应hbibernate里面的数据类型，否则映射不正确！
registerHibernateType(Types.NVARCHAR, Hibernate.STRING.getName());
registerHibernateType(Types.LONGVARCHAR, Hibernate.TEXT.getName());
//registerHibernateType(Types.DECIMAL, Hibernate.BIG_DECIMAL.getName());


// registerHibernateType(Types.LONGVARCHAR, 65535, "text");//.LONGVARCHAR
参考http://blog.csdn.net/qq804702802/article/details/47754875

然后在hibernate.cfg.xml配置不要使用原生的hibernate查询 SQL

第二种创建具体代码如下UserInfoImpl.java

@Override
public List getListBySql()
// TODO Auto-generated method stub
List list = new ArrayList();
Transaction tr = null;
Session session = null;
try
session = getSession();
tr = session.beginTransaction();
String hql = "select * from UserInfo";

                        //创建sql查询

SQLQuery query = session.createSQLQuery(hql); 

                       //指定UserInfo.hbm.xmlColumn 以及指定Hibernate数据类型一直

query.addScalar("U_Name", Hibernate.STRING);
query.addScalar("U_Pwd", Hibernate.STRING);
list = query.list();
tr.commit();
System.out.println(hql);
catch (HibernateException e)
// TODO Auto-generated catch block
e.printStackTrace();
tr.rollback();



return list;



@Override
public List<UserInfo> getListBySqlQ()
// TODO Auto-generated method stub
// TODO Auto-generated method stub
List<UserInfo> list = new ArrayList<UserInfo>();
Transaction tr = null;
Session session = null;
try
session = getSession();
tr = session.beginTransaction();
String hql = "select * from UserInfo";//添加一个实体
list = session.createSQLQuery(hql).addEntity(UserInfo.class).list();
// list=query.list();
tr.commit();
System.out.println(hql);
catch (HibernateException e)
// TODO Auto-generated catch block
e.printStackTrace();
tr.rollback();



return list;

最后测试

package com.util;


import java.util.List;


import com.bean.LogInfo;
import com.bean.UserInfo;
import com.dao.UserDao;
import com.dao.impl.UserInfoImpl;


public class TestUser
public static void main(String[] args)
UserDao dao = new UserInfoImpl();
//返回object数组
List<Object[]> list = dao.getListBySql();
//逻辑与 先判断不为空 否则报NullPonitException
if (list != null && list.size() > 0)

for (Object[] objects : list)

                                    //打印所有UserInfo的U_Name
System.out.println(objects[0]);

效果图