List＜Map＜String, String＞＞ 形式 list根据 每个map中的key排序

Posted 2023-02-02 小山峰的编程之路

		List<Map<String, String>> listMap = new ArrayList<>();
        Map<String, String> map1 = new HashMap<>();
        map1.put("id","01");
        map1.put("name","111");
        listMap.add(map1);

        Map<String, String> map2 = new HashMap<>();
        map2.put("id","02");
        map2.put("name","222");
        listMap.add(map2);

        Map<String, String> map5 = new HashMap<>();
        map5.put("id","05");
        map5.put("name","555");
        listMap.add(map5);

        Map<String, String> map4 = new HashMap<>();
        map4.put("id","04");
        map4.put("name","444");
        listMap.add(map4);

        Map<String, String> map3 = new HashMap<>();
        map3.put("id","03");
        map3.put("name","333");
        listMap.add(map3);

        Map<String, String> map7 = new HashMap<>();
        map7.put("id","07");
        map7.put("name","777");
        listMap.add(map7);

        System.out.println(listMap); 
        // [name=111, id=01, name=222, id=02, name=555, id=05, name=444, id=04, name=333, id=03, name=777, id=07]
        
		// 排序
        List<Map<String, String>> list = listMap.stream().sorted((Comparator.comparingInt(o -> Integer.parseInt(o.get("id"))))).collect(Collectors.toList());

        System.out.println(list);
        //[name=111, id=01, name=222, id=02, name=333, id=03, name=444, id=04, name=555, id=05, name=777, id=07]