采用libxml2解析xml资源

Posted 2022-12-06 alen_xie

通过分析xml资源，发现它不是一个标准的xml资源，通过调用xml解析

xmlXPathObjectPtr getNodeset(xmlDocPtr doc, const xmlChar *xpath)

    xmlXPathContextPtr context;
    xmlXPathObjectPtr result;
    context = xmlXPathNewContext(doc);
    if (context == NULL)
    
        printf("context is NULL, [%s, %d]\\n", __FUNCTION__, __LINE__);
        return NULL;
    
    result = xmlXPathEvalExpression(xpath, context);
    xmlXPathFreeContext(context);
    if (result == NULL)
    
        printf("xmlXPathEvalExpression return NULL, [%s, %d]\\n", __FUNCTION__, __LINE__);
        return NULL;
    
    if (xmlXPathNodeSetIsEmpty(result->nodesetval))
    
        xmlXPathFreeObject(result);
        printf("nodeset is empty, [%s, %d]\\n", __FUNCTION__, __LINE__);
        return NULL;
    
    return result;

xmlXPathObjectPtr getNodeset(xmlDocPtr doc, const xmlChar *xpath);
BOOL ParseFreeiIptvEpgInforFunc(char *pcDownData, int iGetTotalLen, FREEI_IPTV_EPG *pstOTTData)

	int iIndex = 0;
	BOOL bRetuFlg = FALSE;
	xmlDocPtr doc;
	xmlXPathObjectPtr xml_entry = NULL;
	xmlChar *xpath = BAD_CAST("/tv/programme");

	if (pcDownData == NULL)
	
		printf ("[%s, %d] not malloc  xml memory\\n", __FUNCTION__, __LINE__);
		return bRetuFlg;
	
	doc = xmlReadMemory(pcDownData, iGetTotalLen, "noname.xml", NULL, 0);
	if (doc == NULL)
	
		return bRetuFlg;
	

	xml_entry = getNodeset(doc, xpath);
	if (xml_entry)
	
	    xmlNodeSetPtr nodeset = xml_entry->nodesetval;
	    xmlNodePtr cur;
	    xmlAttrPtr attrPtr;
        pstOTTData->pstFreIvEpgList = (FREEI_IPTV_EPG_LIST *)GSOS_Malloc(sizeof(FREEI_IPTV_EPG_LIST)*(nodeset->nodeNr));
    	if (NULL == pstOTTData->pstFreIvEpgList)
    	
    		return bRetuFlg;
    	
    	pstOTTData->iEPGTotal = nodeset->nodeNr;
	    for (iIndex=0; iIndex < nodeset->nodeNr; iIndex++)
	    
	        cur = nodeset->nodeTab[iIndex];
	        attrPtr = cur->properties;
            while(NULL != attrPtr)
            
                if (!xmlStrcmp(attrPtr->name, BAD_CAST "start"))
                
                    xmlChar* szAttr = xmlGetProp(cur, BAD_CAST "start");
                    snprintf (pstOTTData->pstFreIvEpgList[iIndex].acStartTime, \\
                    		sizeof(pstOTTData->pstFreIvEpgList[iIndex].acStartTime), "%s", szAttr);
                    xmlFree(szAttr);
                
                if (!xmlStrcmp(attrPtr->name, BAD_CAST "stop"))
                
                    xmlChar* szAttr = xmlGetProp(cur, BAD_CAST "stop");
                    snprintf (pstOTTData->pstFreIvEpgList[iIndex].acStopTime, \\
                    		sizeof(pstOTTData->pstFreIvEpgList[iIndex].acStopTime), "%s", szAttr);
                    xmlFree(szAttr);
                
                attrPtr = attrPtr->next;
            

	        cur = cur->xmlChildrenNode;
	        while (NULL != cur)
	        
	            if (!xmlStrcmp(cur->name, (const xmlChar *)"title"))
	            
	            	snprintf (pstOTTData->pstFreIvEpgList[iIndex].title, \\
						sizeof(pstOTTData->pstFreIvEpgList[iIndex].title), "%s", \\
						((char*)XML_GET_CONTENT(cur->xmlChildrenNode)));
	            
	            else if (!xmlStrcmp(cur->name, (const xmlChar *)"desc"))
	            
	            	snprintf (pstOTTData->pstFreIvEpgList[iIndex].desc, \\
	            			sizeof(pstOTTData->pstFreIvEpgList[iIndex].desc), "%s",\\
	            			((char*)XML_GET_CONTENT(cur->xmlChildrenNode)));
	            
	            cur = cur->next;
	        
	    
	    xmlXPathFreeObject(xml_entry);
	    bRetuFlg = TRUE;
	
	return bRetuFlg;

然后就可以解析获取到资源了。