[C/C++]详解STL容器9-基于红黑树模拟实现map和set

Posted 2022-10-16 TT在长大

本文基于红黑树模拟实现map和set，首先对之前模拟实现的红黑树做了一些改造，之后对map和set做了模拟实现。前文：[C/C++]详解STL容器7--红黑树的介绍及部分模拟实现_RMA515T的博客-CSDN博客

目录

一、红黑树的改造

节点类型

迭代器

反向迭代器

改造后的红黑树

二、map模拟实现

三、set模拟实现

总结

---

一、红黑树的改造

因为关联式容器中存储的是<key, value>的键值对，因此k为key的类型，V如果是map，则为pair<K, V>; 如果是set，则为k；KeyOfV: 通过V来获取key的一个仿函数类。

节点类型

template<class T>				//pair类型的T
struct RBTreeNode					//节点结构体

	RBTreeNode<T>* _left;		//左子树
	RBTreeNode<T>* _right;		//右子树
	RBTreeNode<T>* _parent;		//父节点

	T _data;

	Colour _col;

	RBTreeNode(const T& x)	//构造函数
		: _left(nullptr)
		, _right(nullptr)
		, _parent(nullptr)
		, _data(x)
		, _col(RED)
	
;

迭代器

template<class T, class Ref, class Ptr>
struct __TreeIterator

	typedef Ref reference;
	typedef Ptr pointer;

	typedef RBTreeNode<T> Node;
	typedef __TreeIterator<T, Ref, Ptr> Self; 

	Node* _node;

	__TreeIterator(Node* node)
		:_node(node)
	

	Ref operator*()		//*返回引用
	
		return _node->_data;
	

	Ptr operator->()		//->返回指针 可以直接用
	
		return &_node->_data;
	

	bool operator != (const Self& s) const
	
		return _node != s._node;
	

	bool operator == (const Self& s) const
	
		return _node == s._node;
	

	Self operator++()
	
		if (_node->_right)
		
			Node* left = _node->_right;
			while (left->_left)
			
				left = left->_left;
			

			_node = left;
		
		else
		
			Node* cur = _node;
			Node* parent = _node->_parent;
			
			while (parent&& cur == parent->_right)
			
				cur = cur->_parent;
				parent = parent->_parent;
			

			_node = parent;
		

		return *this;
	

	Self operator--()
	
		if (_node->_left)
		
			Node* right = _node->_left;
			while (right->_left)
			
				right = right->_left;
			

			_node = right;
		
		else
		
			Node* cur = _node;
			Node* parent = _node->_parent;

			while (parent && cur == parent->_left)
			
				cur = cur->_parent;
				parent = parent->_parent;
			

			_node = parent;
		

		return *this;
	
;

反向迭代器

（这里写了一个反向迭代器适配器）

template<class Iterator>
struct ReverseIterator

	typedef typename Iterator::reference Ref;
	typedef typename Iterator::pointer Ptr;
	typedef ReverseIterator<Iterator> Self;

	Iterator _it;

	ReverseIterator(Iterator it)
		:_it(it)
	

	Ref operator*()		//*返回引用
	
		return *_it;
	

	Ptr operator->()		//->返回指针 可以直接用
	
		return _it.operator->();
	

	bool operator != (const Self& s) const
	
		return _it != s._it;
	

	bool operator == (const Self& s) const
	
		return _it == s._it;
	

	Self operator++()
	
		--_it;
		return *this;
	

	Self operator--()
	
		++_it;
		return *this;
	
	
;

改造后的红黑树

#pragma once
#include<iostream>
#include"RIterator.h"

using namespace std;

enum Colour		//红黑树颜色枚举

	RED,
	BLACK,
;

template<class T>				//pair类型的T
struct RBTreeNode					//节点结构体

	RBTreeNode<T>* _left;		//左子树
	RBTreeNode<T>* _right;		//右子树
	RBTreeNode<T>* _parent;		//父节点

	T _data;

	Colour _col;

	RBTreeNode(const T& x)	//构造函数
		: _left(nullptr)
		, _right(nullptr)
		, _parent(nullptr)
		, _data(x)
		, _col(RED)
	
;

template<class T, class Ref, class Ptr>
struct __TreeIterator

	typedef Ref reference;
	typedef Ptr pointer;

	typedef RBTreeNode<T> Node;
	typedef __TreeIterator<T, Ref, Ptr> Self; 

	Node* _node;

	__TreeIterator(Node* node)
		:_node(node)
	

	Ref operator*()		//*返回引用
	
		return _node->_data;
	

	Ptr operator->()		//->返回指针 可以直接用
	
		return &_node->_data;
	

	bool operator != (const Self& s) const
	
		return _node != s._node;
	

	bool operator == (const Self& s) const
	
		return _node == s._node;
	

	Self operator++()
	
		if (_node->_right)
		
			Node* left = _node->_right;
			while (left->_left)
			
				left = left->_left;
			

			_node = left;
		
		else
		
			Node* cur = _node;
			Node* parent = _node->_parent;
			
			while (parent&& cur == parent->_right)
			
				cur = cur->_parent;
				parent = parent->_parent;
			

			_node = parent;
		

		return *this;
	

	Self operator--()
	
		if (_node->_left)
		
			Node* right = _node->_left;
			while (right->_left)
			
				right = right->_left;
			

			_node = right;
		
		else
		
			Node* cur = _node;
			Node* parent = _node->_parent;

			while (parent && cur == parent->_left)
			
				cur = cur->_parent;
				parent = parent->_parent;
			

			_node = parent;
		

		return *this;
	
;

template<class K, class T, class KeyOfT>		//通过仿函数来取key的值进行比较
class RBTree

	typedef RBTreeNode<T> Node;
private:
	Node* _root;

	void RotateR(Node* parent)
	
		Node* subL = parent->_left;
		Node* subLR = subL->_right;
		Node* parentP = parent->_parent;

		if (subLR)							//左子树的右子树连接到父的右
			subLR->_parent = parent;

		parent->_left = subLR;
		subL->_right = parent;
		parent->_parent = subL;

		// 如果parent是根节点，根新指向根节点的指针
		if (parent == _root)
		
			_root = subL;
			subL->_parent = nullptr;
		
		else
		
			// 如果parent是子树，可能是其双亲的左子树，也可能是右子树
			if (parentP->_left == parent)
				parentP->_left = subL;
			else
				parentP->_right = subL;

			subL->_parent = parentP;
		
	

	void RotateL(Node* parent)
	
		Node* subR = parent->_right;
		Node* subRL = subR->_left;
		Node* parentP = parent->_parent;

		if (subRL)
			subRL->_parent = parent;

		parent->_right = subRL;
		subR->_left = parent;
		parent->_parent = subR;

		// 如果parent是根节点，根新指向根节点的指针
		if (parent == _root)
		
			_root = subR;
			subR->_parent = nullptr;
		
		else
		
			// 如果parent是子树，可能是其双亲的左子树，也可能是右子树
			if (parentP->_left == parent)
				parentP->_left = subR;
			else
				parentP->_right = subR;

			subR->_parent = parentP;
		
	

	void _InOrder(Node* root)
	
		if (root == nullptr)
		
			return;
		

		_InOrder(root->_left);
		cout << root->_kv.first << ':' << root->_kv.second << endl;
		_InOrder(root->_right);
	

	bool _CheckBlance(Node* root, int BlackNum, int count)
	
		if (root == nullptr)
		
			if (count == BlackNum)
				return true;

			cout << "黑色节点的数量不相等" << endl;
			return false;
		

		if (root->_col == RED && root->_parent->_col == RED)
		
			cout << "存在连续的红色节点" << endl;
			return false;
		

		if (root->_col == BLACK)
			count++;
		return _CheckBlance(root->_left, BlackNum, count)					//递归处理每个边
			&& _CheckBlance(root->_right, BlackNum, count);
	

	void _Destory(Node* root)
	
		if (root == nullptr)
		
			return;
		

		_Destory(root->_left);
		_Destory(root->_right);

		delete root;
	

public:
	typedef __TreeIterator < T, T&, T* > iterator;
	typedef __TreeIterator < T, const T&, const T* > const_iterator;
	typedef ReverseIterator<iterator> reverse_iterator;

	RBTree()
		:_root(nullptr)
	

	~RBTree()
	
		_Destory(_root);
		_root = nullptr;
	

	reverse_iterator rbegin()
	
		Node* right= _root;
		while (right && right->_right)			//最左
		
			right = right->_right;
		

		return reverse_iterator(right);
	

	reverse_iterator rend()
	
		return reverse_iterator(nullptr);
	

	iterator begin()
	
		Node* left = _root;
		while (left && left->_left)			//最左
		
			left = left->_left;
		

		return iterator(left);
	

	iterator end()
	
		return iterator(nullptr);
	

	Node* Find(const K& key)
	
		KeyOfT kot;				//
		Node* cur = _root;
		while (cur)
		
			if (kot(cur->_data) > key)
			
				cur = cur->_left;
			
			else if (kot(cur->_data) < key)
			
				cur = cur->_right;
			
			else
			
				return cur;
			
		

		return nullptr;
	

	pair<iterator, bool> Insert(const T& data)
	
		if (_root == nullptr)
		
			_root = new Node(data);
			_root->_col = BLACK;
			return make_pair(iterator(_root), true);
		

		KeyOfT kot;

		Node* parent = nullptr;
		Node* cur = _root;
		while (cur)
		
			if (kot(cur->_data) > kot(data))
			
				parent = cur;
				cur = cur->_left;
			
			else if (kot(cur->_data) < kot(data))
			
				parent = cur;
				cur = cur->_right;
			
			else
			
				return make_pair(iterator(cur), false);
			
		

		Node* newNode = new Node(data);
		newNode->_col = RED;
		if (kot(parent->_data) > kot(data))
		
			parent->_left = newNode;
			newNode->_parent = parent;
		
		else
		
			parent->_right = newNode;
			newNode->_parent = parent;
		
		cur = newNode;

		while (parent && parent->_col == RED)		//违反规则三
		
			Node* grandfather = parent->_parent;

			if (parent == grandfather->_left)			//左半边
			
				Node* uncle = grandfather->_right;

				if (uncle && uncle->_col == RED)		//情况一
				
					uncle->_col = BLACK;
					grandfather->_col = RED;
					parent->_col = BLACK;

					cur = grandfather;			//迭代
					parent = cur->_parent;
				
				else							//情况2.3
				
					if (cur == parent->_left)		//单侧
					
						RotateR(grandfather);

						grandfather->_col = RED;
						parent->_col = BLACK;
					
					else					//折
					
						RotateL(parent);
						RotateR(grandfather);

						cur->_col = BLACK;
						grandfather->_col = RED;
					

					break;		//黑色数量无变化，不需要向上
				
			
			else         // parent == grandfather->_right
			
				Node* uncle = grandfather->_left;
				if (uncle && uncle->_col == RED)		//情况一
				
					uncle->_col = BLACK;
					grandfather->_col = RED;
					parent->_col = BLACK;

					cur = grandfather;			//迭代
					parent = cur->_parent;
				
				else							//情况2.3
				
					if (cur == parent->_right)		//单侧
					
						RotateL(grandfather);

						grandfather->_col = RED;
						parent->_col = BLACK;
					
					else					//折
					
						RotateR(parent);
						RotateL(grandfather);

						cur->_col = BLACK;
						grandfather->_col = RED;
					

					break;
				
			
		

		_root->_col = BLACK;		//插入结束再次将根变为黑

		return make_pair(iterator(newNode), true);
	

	bool CheckBlance()			//检查是否为红黑树，每个路径的黑色节点数相等，
	
		if (_root == nullptr)
		
			return true;
		

		if (_root->_col == RED)
		
			return false;
		

		int BlackNum = 0;
		Node* left = _root;		//找最左路径的黑节点个数，确定基准
		while (left)
		
			if (left->_col == BLACK)
				BlackNum++;

			left = left->_left;
		

		int count = 0;		
		return _CheckBlance(_root, BlackNum, count);
	

	void InOrder()
	
		_InOrder(_root);

		cout << endl;
	
;

二、map模拟实现

#pragma once
#include"RBTree.h"

namespace zht

	template<class K, class V>
	class map
	
		struct MapKeyOfT				//包装仿函数，重载（）
		
			const K& operator()(const pair<const K, V>& kv)
			
				return kv.first;
			
		;
	public:
		typedef typename RBTree<K, pair<const K, V>, MapKeyOfT>::iterator iterator;
		typedef typename RBTree<K, pair<const K, V>, MapKeyOfT>::reverse_iterator reverse_iterator;

		reverse_iterator rbegin()
		
			return _t.rbegin();
		

		reverse_iterator rend()
		
			return _t.rend();
		

		iterator begin()
		
			return _t.begin();
		

		iterator end()
		
			return _t.end();
		

		pair<iterator, bool> insert(const pair<const K, V>& kv)
		
			return _t.Insert(kv);
		

		V& operator[](const K& key)				//直接插入
		
			pair<iterator, bool> ret = insert(make_pair(key, V()));
			return ret.first->second;
		
	private:
		RBTree<K, pair<const K, V>, MapKeyOfT> _t;
	;

三、set模拟实现

#pragma once
#pragma once
#include"RBTree.h"

namespace zht

	template<class K, class V>
	class set
	
		struct SetKeyOfT				//包装仿函数，重载（）
		
			const K& operator()(const K& key)
			
				return key;
			
		;
	public:
		typedef typename RBTree<K, K, SetKeyOfT>::iterator iterator;
		typedef typename RBTree<K, K, SetKeyOfT>::reverse_iterator reverse_iterator;

		reverse_iterator rbegin()
		
			return _t.rbegin();
		

		reverse_iterator rend()
		
			return _t.rend();
		

		iterator begin()
		
			return _t.begin();
		

		iterator end()
		
			return _t.end();
		

		pair<iterator, bool> insert(const K& key)
		
			return _t.Insert(key);
		
	private:
		RBTree<K, K, SetKeyOfT> _t;
	;

总结

map和set的底层为红黑树，因此只需在内部封装一棵红黑树，即可将该容器实现出来。