Java Do While循环问题
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编辑,只有锅值不循环的问题。
我正在开发一个简单的赌博游戏中我的循环问题。游戏完成了我想要的一切,直到它循环回来。我不希望锅重置回我设置的静态$ 100金额。它也没有给新的骰子卷。固定(谢谢Prodian)。似乎循环将继续重置回原始数量,并且不会考虑最后一轮。我有一种感觉,这只是一个错误的变量放置的问题,但我已经尝试过移动它们,我只是无法绕过一个解决方案。任何帮助将不胜感激!
import java.util.Scanner;
import java.util.Random;
public class gamblinggame {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
Random ran = new Random();
double bet;
double pot = 100;
int r1 = ran.nextInt(6) + 1;
int r2 = ran.nextInt(6) + 1;
int r3 = ran.nextInt(6) + 1;
System.out.println("*** Gambling Game ***");
System.out.println("Your starting pot is $100, please place a bet less than or equal to the pot.");
do {
r1 = ran.nextInt(6) + 1; // continues to re-roll dice
r2 = ran.nextInt(6) + 1;
r3 = ran.nextInt(6) + 1;
bet = scanner.nextDouble();
if (bet > pot) {
System.out.println("Invalid amount. Please place a new bet.");
continue;
}
if (bet >= 1) {
System.out.println("Your new pot is $" + (pot - bet) + ".");
System.out.println("Rolling the dice.");
System.out.println(
"You rolled " + r1 + ", " + r2 + ", " + r3 + ". The total amount rolled is " + (r1 + r2 + r3));
if (r1 == r2 || r1 == r3 || r2 == r3) {
System.out.println("You win DOUBLE your bet back!");
System.out.println("Your new pot is $" + (pot + (bet * 2)) + ".");
} else if (r1 == r2 && r1 == r3 && r2 == r3) {
System.out.println("You win TRIPLE your bet back!");
System.out.println("Your new pot is $" + (pot + (bet * 3)) + ".");
} else if (r1 + r2 + r3 >= 10) {
System.out.println("You win your bet back!");
System.out.println("Your new pot is $" + (pot) + ".");
}
System.out.println("Enter a new bet equal to or below the pot.");
}
if (bet > pot) {
System.out.println("Invalid amount. Please place a new bet.");
continue;
}
if (bet == 0) {
System.out.println("Game Over. Please play again!");
break;
}
} while (pot > 0);
}
}
答案
你应该重新掷骰子,重新掷骰的解决方案是:
....
int r1 = ran.nextInt(6) + 1;
int r2 = ran.nextInt(6) + 1;
int r3 = ran.nextInt(6) + 1;
....
do{
r1 = ran.nextInt(6) + 1; // again random at the start of do-while loop is necessary
r2 = ran.nextInt(6) + 1;
r3 = ran.nextInt(6) + 1;
....
}.....
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