在嵌套for循环内，打印字符串“。”并在满足条件时将其替换为其他字符。 MOOC Java Week 10'Dungeon'
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我正在研究这个项目MOOC Java Week 10 Exercise 33
当玩家/吸血鬼位置X和Y等于网格的X和Y时，我希望String .被玩家/吸血鬼符号（String @和v）取代。 （网格的高度和宽度由字符串.打印）。问题出在类Dungeon，方法printMap()。
班级球员
public class Player {
private final String symbol;
private int posX, posY, width, height;
public Player(String symbol, int width, int height) {
this.symbol = symbol;
this.posX = 0;
this.posY = 0;
this.width = width - 1;
this.height = height - 1;
}
public String getSymbol() {
return symbol;
}
public int getPosX() {
return posX;
}
public int getPosY() {
return posY;
}
public void setPosX(int x) {
posY = x;
}
public void setPosY(int y) {
posY = y;
}
public String getPos() {
return posX + " " + posY;
}
public void keyMap(String keyPressed) {
boolean y = posY > 0;
boolean h = posY < height;
boolean x = posX > 0;
boolean w = posX < width;
if (keyPressed.equalsIgnoreCase("w")) {
if (y) {
posY--;
}
} else if (keyPressed.equalsIgnoreCase("s")) {
if (h) {
posY++;
}
} else if (keyPressed.equalsIgnoreCase("a")) {
if (x) {
posX--;
}
} else if (keyPressed.equalsIgnoreCase("d")) {
if (w) {
posX++;
}
}
}
@Override
public String toString() {
return symbol + " " + posX + " " + posY;
}
}
吸血鬼类
package dungeon;
import java.util.Random;
public class Vampire {
private String symbol;
private int posX, posY, width, height;
private final Random rand = new Random();
public Vampire(String symbol, int width, int height) {
this.symbol = symbol;
this.posX = rand.nextInt(width);
this.posY = rand.nextInt(height);
this.width = width - 1;
this.height = height - 1;
}
public String getSymbol() {
return symbol;
}
public int getPosX() {
return posX;
}
public int getPosY() {
return posY;
}
public String getPos() {
return posX + " " + posY;
}
public void setPosX(int x) {
posX = x;
}
public void setPosY(int y) {
posY = y;
}
public void resetPos() {
posX = rand.nextInt(width);
posY = rand.nextInt(height);
checkStartPos();
}
public void checkStartPos() {
while (posX == 0 || posY == 0) {
if (posX == 0) {
posX = rand.nextInt(width);
} else if (posY == 0) {
posY = rand.nextInt(height);
}
}
}
public void move() {
boolean y = posY > 0;
boolean h = posY < height;
boolean x = posX > 0;
boolean w = posX < width;
int direction = rand.nextInt(4);
switch (direction) {
case 0:
if (y) {
posY--;
break;
}
case 1:
if (h) {
posY++;
break;
}
case 2:
if (x) {
posX--;
break;
}
case 3:
if (w) {
posX++;
break;
}
}
}
@Override
public String toString() {
return symbol + " " + posX + " " + posY;
}
}
类地牢
package dungeon;
import java.util.ArrayList;
import java.util.List;
public class Dungeon {
private Player player;
private List<Vampire> vampires = new ArrayList<Vampire>();
private int width;
private int height;
private int BP; // lamp battery point
private boolean canVampireMove;
public Dungeon(int width, int height, int vampires, int moves, boolean vampiresMove) {
this.player = new Player("@", width, height);
this.width = width;
this.height = height;
this.BP = moves;
this.canVampireMove = vampiresMove;
for (int i = 0; i < vampires; i++) {
this.vampires.add(new Vampire("v", width, height));
}
}
public void printCoordinate() {
System.out.println(BP);
System.out.println("
" + player);
for (Vampire each : vampires) {
System.out.println(each);
}
}
public void printMap() {
for (int y = 0; y < height; y++) {
for (int x = 0; x < width; x++) {
if (player.getPos().equals(x + " " + y)) {
System.out.print(player.getSymbol()); // print "@"
}
for (int v = 0; v < vampires.size(); v++) {
if (vampires.get(v).getPos().equals(x + " " + y)) {
System.out.print(vampires.get(v).getSymbol()); // print "v"
}
}
System.out.print(".");
}
System.out.println();
}
}
}
班级主要
package dungeon;
public class Main {
public static void main(String[] args) {
Dungeon d = new Dungeon(5, 5, 1, 14, true); // width of grid, height of grid (grid printed by string "."), vampires, moveRemaining, canVampireMove
d.printCoordinate();
d.printMap();
}
}
输出是
@ 0 0（球员x，y） v 3 0（吸血鬼x，y）
@ ... in .. ..... ..... ..... .....
字符串@应该已经取代了第一个.，而v应该取代第三个.。
预期产出
@ 0 0（球员x，y） v 3 0（吸血鬼x，y）
@ .v .. ..... ..... ..... .....
答案
问题是你要为player和vampire占据的位置打印多个字符。你的代码检查给定的位置是否被player占用，如果是，打印@但是它仍会打印点。
您应该对此进行限制，以便每个位置只打印一个字符。例如像这样的东西。
if (positions is occupied by player) {
print player
} else if (position is occupied by a vampire) {
print vampire
} else {
else print dot
}
另一答案
有更好的方法来做这个像二维数组和hashmap。但这是快速解决方案。没有测试它，但它应该工作。
public void printMap（）{
for (int y = 0; y < height; y++) {
for (int x = 0; x < width; x++) {
if (player.getPos().equals(x + " " + y)) {
System.out.print(player.getSymbol()); // print "@"
} else if {
for (int v = 0; v < vampires.size(); v++) {
if (vampires.get(v).getPos().equals(x + " " + y)) {
System.out.print(vampires.get(v).getSymbol()); // print "v"
}
}
} else {
System.out.print(".");
}
System.out.println();
}
}
}
另一答案
我通过创建一个布尔方法解决了这个问题。
public void printMap() {
for (int y = 0; y < height; y++) {
for (int x = 0; x < width; x++) {
if (player.getPos().equals(x + " " + y)) {
System.out.print(player.getSymbol());
} else if (getVampires(x, y)) {
System.out.print("v");
} else {
System.out.print(".");
}
}
System.out.println();
}
}
public boolean getVampires(int x, int y) {
for (int v = 0; v < vampires.size(); v++) {
if (vampires.get(v).getPos().equals(x + " " + y)) {
return true;
}
}
return false;
}
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