2.(10分)设有一个带头结点,由正整数组成的无序单链表,头指针为L。。。。。整个问题如下
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2.(10分)设有一个带头结点,由正整数组成的无序单链表,头指针为L,
Typedef struct Lnode
int data;
struct Lnode *next;
Lnode,*Linklist;
Linklist L;
给出完成下列功能的算法并分析算法时间复杂度:
①找出最小值结点,且打印该数值;
②若该数值是奇数,则将其与直接后继结点(若存在)的数值交换;
③若该数值是偶数,则将其直接后继结点(若存在)删除;
数据结构问题,用C解决
#include <stdlib.h>
typedef struct Lnode
int data;
struct Lnode *next;
Lnode,*Linklist;
Linklist L;
Linklist ListInit(Linklist Head, int n)
Linklist p;
int i;
for(i = 0; i < n; i ++)
p = (Linklist)malloc(sizeof(Lnode));
p->next = Head;
Head = p;
return Head;
Linklist ListReleas(Linklist Head)
Linklist p = Head;
while(Head)
p = Head;
Head=p->next;
free(p);
return Head;
int main()
Linklist Head = NULL, p = NULL, q = NULL;
int count[3] = 0, n, inum;
printf("输入节点数:");
scanf("%d", &n);
Head = ListInit(Head, n);
printf("输入每个节点值(共%d个):\n", n);
p = Head;
while( p != NULL )
scanf("%d", &p->data);
p = p->next;
//找出最小值
q = Head;
p = Head;
while( p != NULL )
if(p->data < q->data)
q = p;
p = p->next;
printf("最小值为:%d\n",q->data);
//以下为第一次输出
p = Head;
while( p != NULL )
printf("%d ", p->data);
p = p->next;
printf("\n");
//奇偶判断并进行处理
if(q->data % 2)
if(q->next)
inum = q->data;
q->data = q->next->data;
q->next->data = inum;
else
while(q->next)
p = q->next;
q->next = p->next;
free(p);
//以下为修改后输出
p = Head;
while( p != NULL )
printf("%d ", p->data);
p = p->next;
printf("\n");
ListReleas(Head);
return 0;
参考技术A 链表问题大全!!!刚出炉的还热乎呢!!
#include <stdio.h>
#include <stdlib.h>
typedef struct node
int nDate;
struct node *pstnext;
Node;
//链表输出
void output(Node *head)
Node *p = head->pstnext;
while(NULL != p)
printf("%d ", p->nDate);
p = p->pstnext;
printf("\r\n");
//链表建立
Node* creat()
Node *head = NULL, *p = NULL, *s = NULL;
int Date = 0, cycle = 1;
head = (Node*)malloc(sizeof(Node));
if(NULL == head)
printf("分配内存失败\r\n");
return NULL;
head->pstnext = NULL;
p = head;
while(cycle)
printf("请输入数据且当输入数据为0时结束输入\r\n");
scanf("%d", &Date);
if(0 != Date)
s = (Node*)malloc(sizeof(Node));
if(NULL == s)
printf("分配内存失败\r\n");
return NULL;
s->nDate = Date;
p->pstnext = s;
p = s;
else
cycle = 0;
p->pstnext = NULL;
return(head);
//单链表测长
void length(Node *head)
Node *p = head->pstnext;
int j=0;
while(NULL != p)
p = p->pstnext;
j++;
printf("%d\r\n", j);
//链表按值查找
void research_Date(Node *head, int date)
Node *p;
int n=1;
p = head->pstnext;
while(NULL != p && date != p->nDate)
p = p->pstnext;
++n;
if(NULL == p)
printf("链表中没有找到该值");
else if(date == p->nDate)
printf("要查找的值%d在链表中第%d个位置\r\n", date, n);
return;
//按序号查找
void research_Number(Node *head, int Num)
Node *p=head;
int i = 0;
while(NULL != p && i < Num)
p = p->pstnext;
i++;
if(p == NULL)
printf("查找位置不合法\r\n");
else if(i == 0)
printf("查找位置为头结点\r\n");
else if(i == Num)
printf("第%d个位置数据为%d\r\n", i, p->nDate);
//在指定元素之前插入新结点
void insert_1(Node *head, int i, int Newdate)
Node *pre = head, *New = NULL;
int j = 0;
while(NULL != pre && j < i-1)
pre = pre->pstnext;
j++;
if(NULL == pre || j > i-1)
printf("插入位置不存在\r\n");
else
New = (Node*)malloc(sizeof(Node));
if(NULL == New)
printf("分配内存失败\r\n");
return;
New->nDate = Newdate;
New->pstnext = pre->pstnext;
pre->pstnext = New;
//在指定元素之后插入新结点
void insert_2(Node *head, int i, int Newdate)
Node *pre = head, *New = NULL;
int j = 0;
while(NULL != pre->pstnext && j < i)
pre = pre->pstnext;
j++;
if(j == i)
New = (Node*)malloc(sizeof(Node));
if(NULL == New)
printf("分配内存失败\r\n");
return;
New->nDate = Newdate;
New->pstnext = pre->pstnext;
pre->pstnext = New;
else
printf("插入位置不存在\r\n");
//删除第一个结点
void delete_list(Node *head)
Node *p = head->pstnext;
head->pstnext = p->pstnext;
free(p);
//删除指定结点
void Delete_1(Node *head, int i3)
Node *p = head, *pre = NULL;
int j = 0;
while(NULL != p && j < i3)
pre = p;
p = p->pstnext;
j++;
if(NULL == p)
printf("删除位置不存在\r\n");
else
pre->pstnext = p->pstnext;
free(p);
//指定删除单链表中某个数据,并统计删除此数据的个数
int Delete_2(Node *head, int Delete_date)
int count = 0;
Node *p = head, *q;
while(NULL != p->pstnext)
q = p->pstnext;
if(q->nDate == Delete_date)
p->pstnext = q->pstnext;
free(q);
++count;
else
p = q;
return count;
//链表逆置
void Reverse_list(Node *head)
Node *q, *s;
if(NULL == head->pstnext || NULL == head->pstnext->pstnext)
return;
q = head->pstnext->pstnext;
head->pstnext->pstnext = NULL;
while(NULL != q)
s = q->pstnext;
q->pstnext = head->pstnext;
head->pstnext = q;
q = s;
//单链表的连接
void connect_list(Node *head, Node *head_New)
Node *p = head;
while(NULL != p->pstnext)
p = p->pstnext;
p->pstnext = head_New->pstnext;
void main()
int date, num; //待查找数据
int i3; //指定删除元素的位置
int i1, i2, Newdate_1, Newdate_2; //待插入的新数据
int Delete_date, k; //待删除的数据与其个数
Node *Head = NULL; //定义头结点
Node *Head_New = NULL;
//链表建立
Head = creat();
printf("输出建立的单链表\r\n");
output(Head);
//单链表测长
printf("单链表长度为\r\n");
length(Head);
//链表按值查找
printf("请输入待查找的数据\r\n");
scanf("%d", &date);
research_Date(Head, date);
//链表按序号查找
printf("请输入待查找序号\r\n");
scanf("%d", &num);
research_Number(Head, num);
//在指定第i1个元素之前插入新元素Newdate
printf("在指定第i个元素之前插入新元素Newdate");
printf("请输入i与元素且以逗号间隔\r\n");
scanf("%d,%d", &i1, &Newdate_1);
insert_1(Head, i1, Newdate_1);
printf("插入后新链表\r\n");
output(Head);
//在指定第i2个元素之后插入新元素Newdate
printf("在指定第i个元素之后插入新元素Newdate");
printf("请输入i与元素且以逗号间隔\r\n");
scanf("%d,%d", &i2, &Newdate_2);
insert_2(Head, i2, Newdate_2);
printf("插入后新链表\r\n");
output(Head);
//删除链表第一个结点
delete_list(Head);
printf("输出删除后的链表\r\n");
output_list(Head);
//指定删除i3元素
printf("删除元素的位置\r\n");
scanf("%d", &i3);
Delete_1(Head, i3);
printf("删除后新链表\r\n");
output(Head);
//指定删除单链表中某个数据,并统计删除此数据的个数
printf("请输入待删除的元素\r\n");
scanf("%d", &Delete_date);
k = Delete_2(Head, Delete_date);
printf("删除后新链表\r\n");
output(Head);
printf("删除指定元素在链表中的个数为:");
printf("%d\r\n", k);
//单链表逆置
Reverse_list(Head);
printf("逆置后输出\r\n");
output(Head);
//单链表的连接
printf("建立一个新链表\r\n");
Head_New = creat();
printf("输出新链表");
output(Head);
printf("将新链表连接到原来链表的尾部并输出\r\n");
connect_list(Head, Head_New);
output(Head);
return;
2203: 最小节点(线性表)
2203: 最小节点(线性表)
时间限制: 1 Sec 内存限制: 128 MB提交: 382 解决: 294
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题目描述
(线性表)设有一个由正整数组成的无序(向后)单链表,编写完成下列功能的算法:找出最小值结点,且打印该数值。
输入
输入长度:6
输入数据:3 2 1 4 6 8
输出
1
样例输入
6
11 14 5 6 8 9
样例输出
5
#include<cstdio> #include<cstdlib> #include<iostream> using namespace std; #define MAXN 110 typedef int ElemType; typedef struct LNode { ElemType data; struct LNode * next; }LinkNode; ElemType a[MAXN], e; LinkNode *L; void CreateList(LinkNode *&L, ElemType a[], int n) { LinkNode *r, *s; L = (LinkNode *)malloc(sizeof(LinkNode)); r = L; for(int i = 0; i < n; ++i) { s = (LinkNode *)malloc(sizeof(LinkNode)); s->data = a[i]; r->next = s; r = s; } r->next = NULL; } void GetMin(LinkNode *L, ElemType &e) { LinkNode *p = L->next, *pre = L, *minp, *minpre; minp = p; minpre = pre; while(p != NULL) { if(minp->data > p->data) { minp = p; minpre = pre; } pre = p; p = p->next; } e = minp->data; return ; } int main() { int n; cin >> n; for(int i = 0; i < n; ++i) cin >> a[i]; CreateList(L, a, n); GetMin(L, e); cout << e << endl; return 0; }
!--StartMarkForVirtualJudge-->以上是关于2.(10分)设有一个带头结点,由正整数组成的无序单链表,头指针为L。。。。。整个问题如下的主要内容,如果未能解决你的问题,请参考以下文章
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