oracle中如何只查询一条复合条件的记录，即查到一条记录就返回？

Posted 2023-05-01

参考技术A SQL SERVER
select top 1 * from xxx

ORACLE
select * from xxx where rownum <= 1

My SQL
select * from xxxx limit 1

DB2:
select * from xxx fetch first 1 rows only

Oracle 数据库 - sql语句筛选出符合查询条件的第一条结果实例演示，sql查询结果只显示指定行数的数据方法

默认看到查询条件有 3 条结果，我想只查询出日期最晚的那一条记录。

-- 默认查询条件
select 
settledate as "日期", 
syscalculationmny as "金额" 
from cdmc_interestlist 
where pk_financepay 
in (select pk_financepay from cdmc_financepay where vbillno = 'SFLXQD0036_001') 
order by settledate desc 

把查询条件括起来，加个 rownum=1 的筛选条件就能筛选出 1 行数据。

-- 筛选符合条件的第一条
select * from (
        select 
        settledate as "日期", 
        syscalculationmny as "金额" 
        from cdmc_interestlist 
        where pk_financepay 
        in (select pk_financepay from cdmc_financepay where vbillno = 'SFLXQD0036_001') 
        order by settledate desc 
) where rownum=1

两条数据的话要用小于号，等于号我试过了，查询出的结果为空。

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