在jsp中，如何实现普通用户和管理员登陆后跳转到不同的点jsp页面

Posted 2023-04-21

在jsp中可以通过角色控制表跳转不同的页面。
参考代码如下：

package myservlet;
import mybean.*;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.sql.*;
public class IsLogin extends HttpServlet
public void init(ServletConfig config) throws ServletException
super.init(config);

public void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException,IOException
//接收参数
String user=request.getParameter("user");
String password=request.getParameter("password");
String actor=request.getParameter("actor");
//加载驱动，建立连接
Connection con;
Statement sql;
ResultSet rs;
try
Class.forName("com.microsoft.sqlserver.jdbc.SQLServerDriver");
catch(Exception e)
System.out.print(e);


try
String uri="jdbc:sqlserver://127.0.0.1:1433;DatabaseName=student";
con=DriverManager.getConnection(uri,"sa","940712");//数据库的登录名 sa 940712
sql=con.createStatement();
//通过if语句判断角色，将其账号密码与数据库的userInf内的信息进行比对（角色的账号密码统一存储在UserInf表中）
//若正确，转发至角色对应的登录成功界面；若没有，统一转发至出错界面，提供返回链接供重新登录
if(actor=="student")
rs=sql.executeQuery("select userIs,password from userInf where actor='student'");
while(rs.next())
if(user==rs.getString(1) && password==rs.getString(2))
RequestDispatcher dispatcher=request.getRequestDispatcher("loginSuccessS.jsp");
dispatcher.forward(request,response);


RequestDispatcher dispatcher=request.getRequestDispatcher("loginError.jsp");
dispatcher.forward(request,response);

//普通用户角色控制
else if(actor=="teacher")
rs=sql.executeQuery("select userIs,password from userInf where actor='teacher'");
while(rs.next())
if(user==rs.getString(1) && password==rs.getString(2))
RequestDispatcher dispatcher=request.getRequestDispatcher("loginSuccessT.jsp");
dispatcher.forward(request,response);


RequestDispatcher dispatcher=request.getRequestDispatcher("loginError.jsp");
dispatcher.forward(request,response);

//管理员角色控制
else if(actor=="admin")
rs=sql.executeQuery("select userIs,password from userInf where actor='admin'");
while(rs.next())
if(user==rs.getString(1) && password==rs.getString(2))
RequestDispatcher dispatcher=request.getRequestDispatcher("loginSuccessA.jsp");
dispatcher.forward(request,response);


RequestDispatcher dispatcher=request.getRequestDispatcher("loginError.jsp");
dispatcher.forward(request,response);

catch(SQLException e)
//System.out.print("您的账号或密码错误，请返回重新输入");
RequestDispatcher dispatcher=request.getRequestDispatcher("loginError.jsp");
dispatcher.forward(request,response);


参考技术A 直接使用页面跳转标签就可以了，如果用servlet会稍微复杂一点

Django里自定义用户登陆及登陆后跳转到登陆前页面的实现

def logout(request):
    request.session.flush()
    return HttpResponseRedirect(request.META.get(‘HTTP_REFERER‘, ‘/‘))

class LoginView(View):
    def get(self,request):
        request.session[‘login_from‘] = request.META.get(‘HTTP_REFERER‘, ‘/‘)
        return render(request,‘login.html‘)

    def post(self,request):
        username=request.POST.get(‘username‘,None)
        password=request.POST.get(‘password‘,None)
        try:
            user=authenticate(request,username=username,password=password)
        except:
            user=None
        if user is not None:
            login(request,user)
            request.session[‘is_login‘] = True
            request.session[‘user_id‘] = str(user.id)
            request.session[‘user_name‘] = str(user)
            return HttpResponseRedirect(request.session[‘login_from‘])
        else:
            return HttpResponse(u‘密码不对或者不存在‘)