sql server 2000返回在第一个表中但不在第二个表中的数据

Posted 2023-04-09

准确的说，我有两个表，第一个表中有10000条数据，第二个表中有5000个数据，两个表中有4000个数据是相同的。现在我要查询返回在第一个表中，但是不在第二个表中的6000个数据，怎样写语句

参考技术A Declare @字段1 类型1，@字段2 类型2
Declare @i int
While(i<=6000)
i=i+1
Begin
SELECT @字段1=表1.字段1 @字段2=表1.字段2
FROM 表1
WHERE EXISTS(SELECT * FROM 表2 WHERE 表2.字段1==@字段1 表2.字段2==@字段2)
End 参考技术B Select *
From FirstTable
Where FirstTable.Key not in (Select Key From SecondTable )本回答被提问者采纳

???Sql Server???SQL SERVER ????????????

?????????int   with   ??????   serve   span   ??????   inner   --   blog   

??????:???Sql Server???SQL SERVER ????????????

??????SQL SERVER 2005?????????????????????????????????????????????SQL SERVER 2005???????????????CTE?????????????????????CTE?????????????????????

??????CTE??????????????????Common Table Expression ???SQL SERVER 2005????????????????????????????????????

#??????????????????

1???sql

 1 Create table GroupInfo([Id] int,[GroupName] nvarchar(50),[ParentGroupId] int)
 2 
 3 Insert GroupInfo
 4 
 5 select 0,??????????????????,null union all
 6 
 7 select 1,??????????????????,0 union all
 8 select 2,??????????????????,1 union all
 9 select 3,??????????????????,1 union all
10 select 4,????????????????????????,2 union all
11 select 5,????????????????????????,2 union all
12 select 6,????????????????????????,3 union all
13 select 7,????????????????????????,3 union all
14 
15 select 8, ???????????????,0 union all
16 select 9, ?????????????????????,8 union all
17 select 10,????????????????????????,8 union all
18 select 11,???????????????????????????,9 union all
19 select 12,???????????????????????????,9 union all
20 select 13,??????????????????????????????,10 union all
21 select 14,??????????????????????????????,10 

2????????????

 

#????????????Demo

1???????????????????????????????????????????????????,???????????????????????????

 1 --????????????????????????????????????????????????
 2 with
 3 CTE
 4 as
 5 (
 6     select * from GroupInfo where Id=1
 7     union all
 8     select G.* from CTE inner join GroupInfo as G
 9     on CTE.Id=G.ParentGroupId
10 )
11 select * from CTE order by Id

 

 1 --????????????????????????????????????????????????
 2 with
 3 CTE
 4 as
 5 (
 6     select * from GroupInfo where Id=14
 7     union all
 8     select G.* from CTE inner join GroupInfo as G
 9     on CTE.ParentGroupId=G.Id
10 )
11 select * from CTE order by Id

2?????????????????????

 1 --??????????????????
 2 with
 3 CTE
 4 as
 5 (
 6     select Id,GroupName,ParentGroupId,GroupPath=CAST( GroupName as nvarchar(max)) from GroupInfo where Id=1
 7     union all
 8     select G.*,CAST(CTE.GroupPath+???//???+G.GroupName as nvarchar(max)) as GroupPath from CTE 
 9     inner join GroupInfo as G
10     on CTE.Id=G.ParentGroupId
11 )
12 select * from CTE

 3?????????????????????????????????????????????????????????

 1 --??????id????????????????????????????????????sort??????????????????sort??????????????????????????????????????????????????????
 2 WITH    
 3 CTE
 4 AS 
 5 ( 
 6     SELECT * ,CAST(RIGHT(???000??? + CAST([Id] AS VARCHAR), 3) AS VARCHAR(MAX)) AS sort FROM GroupInfo
 7     WHERE ParentGroupId = 0
 8     UNION ALL
 9     SELECT   GroupInfo.* ,CAST(sort + RIGHT(???000??? + CAST(GroupInfo.[Id] AS VARCHAR),3) AS VARCHAR(MAX)) AS sort
10     FROM CTE
11     INNER JOIN GroupInfo ON CTE.Id = GroupInfo.ParentGroupId
12 )
13 SELECT * FROM CTE ORDER BY sort 

 

4?????????????????????????????????????????????????????????

1 --??????????????????
2 WITH CTE AS (
3     SELECT *,1 AS [Level] FROM GroupInfo WHERE ParentGroupId=0
4     UNION ALL
5     SELECT G.*,CTE.Level+1 FROM GroupInfo as G 
6     JOIN CTE ON CTE.Id =G.ParentGroupId
7 )
8 SELECT * FROM CTE