(4道全A)拼多多2021届提前批-服务端研发工程师笔试
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目录
一、分割矩阵(1-8)(A100%)
代码一:
import java.util.Scanner;
/**
* Created by IntelliJ IDEA.
*
* @Author:
* @Email:
* @Date: 2020/9/1
* @Time: 20:22
* @Version: 1.0
* @Description: Description
*/
public class A
public static void main(String[] args)
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
scanner.close();
for (int i = 1; i <= n; i++)
for (int j = 1; j <= n; j++)
if (i == j || i + j == n + 1 || (n % 2 != 0 && (i == (n + 1) / 2 || j == (n + 1) / 2)))
System.out.print(0);
else if (j < n + 1 - i && j > (float) (n+1) / 2)
System.out.print(1);
else if (j > i && j < (float) (n+1) / 2)
System.out.print(2);
else if (j < i && i < (float) (n+1) / 2)
System.out.print(3);
else if (i < n + 1 - j && i > (float) (n+1) / 2)
System.out.print(4);
else if (i > n + 1 - j && j < (float) (n+1) / 2)
System.out.print(5);
else if (i > j && j > (float) (n+1) / 2)
System.out.print(6);
else if (i < j && i > (float) (n+1) / 2)
System.out.print(7);
else if (i > n + 1 - j && i < (float) (n+1) / 2)
System.out.print(8);
if (j == n)
System.out.println();
else
System.out.print(" ");
二、移动士兵(A)
代码:
/**
* Created by IntelliJ IDEA.
*
* @Author:
* @Email:
* @Date: 2020/9/1
* @Time: 20:50
* @Version: 1.0
* @Description: Description
*/
import java.util.*;
public class Second2
static int [][]a=new int[405][405];
static int [][]col=new int[405][405];
static int []qx=new int[200005];
static int []qy=new int[200005];
static int []siz=new int[200005];
static int []v=new int[200005];
static int cnt,n,m;
static int []kx=0,0,1,-1;
static int []ky=1,-1,0,0;
public static void bfs(int x,int y)
int eh=1,ed=0,eh2=1,ed2=0;
qx[++ed]=x; qy[++ed2]=y;
while(eh<=ed)
int u=qx[eh],v=qy[eh2]; eh++; eh2++; col[u][v]=cnt; siz[col[u][v]]++;
for(int i=0;i<=3;i++)
int tx=u+kx[i],ty=v+ky[i];
if(tx<=0||tx>n||ty<=0||ty>m||col[tx][ty]!=0||a[tx][ty]==0) continue;
qx[++ed]=tx; qy[++ed2]=ty;
public static void main(String[] args)
Scanner S=new Scanner(System.in);
n=S.nextInt(); m=S.nextInt();
for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) a[i][j]=S.nextInt();
for(int i=1;i<=n;i++) for(int j=1;j<=m;j++)
if(a[i][j]==1&&col[i][j]==0) cnt++; bfs(i,j);
int ans=0;
for(int i=1;i<=cnt;i++) ans=Math.max(ans,siz[i]);
for(int i=1;i<=n;i++)
for(int j=1;j<=m;j++)
if(a[i][j]==1) continue;
int tmp=0;
for(int k=0;k<=3;k++)
int tx=i+kx[k],ty=j+ky[k];
if(tx<=0||tx>n||ty<=0||ty>m) continue;
if(v[col[tx][ty]]==0)
v[col[tx][ty]]=1;
tmp+=siz[col[tx][ty]];
ans=Math.max(ans,tmp+1);
for(int k=0;k<=3;k++)
int tx=i+kx[k],ty=j+ky[k];
if(tx<=0||tx>n||ty<=0||ty>m) continue;
v[col[tx][ty]]=0;
int p2=0;
for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) p2+=a[i][j];
System.out.println(Math.min(ans,p2));
三、背包(A了80%)
import java.util.*;
public class zbr01
static int []dp=new int[1000005];
static int []c=new int[500005];
static int []v=new int[500005];
public static void main(String[] args)
Scanner S=new Scanner(System.in);
int n=S.nextInt(),m=S.nextInt(),k=20005;
for(int i=0;i<k;i++) dp[i]=-10000000;
for(int i=1;i<=n;i++)
int w=S.nextInt(),v=S.nextInt();
if(w<0)
for(int j=0;j<k+m+w;j++)
dp[j]=Math.max(dp[j],dp[j-w]+v);
else
for(int j=k+m;j>=w;j--)
dp[j]=Math.max(dp[j],dp[j-w]+v);
int ans=0;
for(int i=k-5;i<=k+m;i++) ans=Math.max(ans,dp[i]);
System.out.println(ans);
四、显著特征(X可以被Y整除)(A100%)
/**
* Created by IntelliJ IDEA.
*
* @Author:
* @Email:
* @Date: 2020/9/1
* @Time: 19:59
* @Version: 1.0
* @Description: Description
*/
import java.util.Scanner;
public class Four2
public static void main(String[] args)
Scanner S = new Scanner(System.in);
long N = S.nextLong();
int M = S.nextInt();
long[] arr = new long[M + 1];
for (int i = 1; i <= M; i++)
arr[i] = S.nextInt();
long ed = pw(2, M), ans = N;
for (int i = 1; i < ed; i++)
long cnt = 0, tmp = 1;
for (int j = 1; j <= M; j++)
if ((i & (1 << (j - 1))) != 0)
cnt++;
tmp = tmp / gcd(tmp, arr[j]) * arr[j];
if (cnt % 2 == 1) ans -= (N / tmp);
else ans += (N / tmp);
System.out.println(N - ans);
public static long pw(long a, long b)
long ans = 1, base = a;
while (b != 0)
if (b % 2 == 1) ans = (ans * base);
base = (base * base);
b >>= 1;
return ans;
public static long gcd(long a, long b)
return b == 0 ? a : gcd(b, a % b);
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