lua5.2调用c++dll

Posted 2023-03-18

cpp源码如下
#include "ELuna.h"

/**/
#define DEBUG_ENGINE
#ifdef DEBUG_ENGINE
//#pragma comment(lib,"../Lib/Lib/Debug/Lua52")
#pragma comment(lib,"../Lib/Debug/Lua52")
#else
#pragma comment(lib,"../Lib/Release/Lua52")
#endif

extern "C" static int Add(lua_State*L)

lua_pushnumber(L, 10);
return 1;

extern "C" static int Sub(lua_State*L)

lua_pushnumber(L, -10);
return 1;


static const struct luaL_Reg testlib[] =
"Add", Add ,
"Sub", Sub ,
NULL, NULL
;

extern "C" __declspec(dllexport) int luaopen_TestDll(lua_State* L)

luaL_newlib(L, testlib);
return 1;


编译后运行lua 得到结果

C:\Users\chenxu>lua
Lua 5.2.3 Copyright (C) 1994-2013 Lua.org, PUC-Rio
> require("TestDll")
multiple Lua VMs detected
stack traceback:
[C]: in ?
[C]: in function 'require'
stdin:1: in main chunk
[C]: in ?
>

参考技术A 这个是lua5.2出现的故障，你在编译的时候生成动态链接库，同时会生成一个lib存根。跟这个存根链接，运行的时候动态连接库跟lua.exe放在一起就好了。

注意 LUA_BUILD_AS_DLL 这个宏。本回答被提问者采纳 参考技术B 编译的时候调用动态链接库lua52.dll 不要用静态链接库

lua能调用dll吗

lua只能通过ffi库调用外部的。比如alien库。

Alien is a Foreign Function Interface (FFI) for Lua. An FFI lets you call functions in dynamic libraries (.so, .dylib, .dll, etc.) from Lua code without having to write, compile and link a C binding from the library to Lua. In other words, it lets you write extensions that call out to native code using just Lua. 参考技术A 可以，只要引擎将lib里面的接口暴露给lua就行了